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2d
comment Explain “homotopy” to me
For that definition to be correct, "map" needs to mean "continuous function". ​ ​
Feb
5
awarded  Nice Question
Feb
4
comment Asymptotic Behavior of Ratio of Random Variables
Er, yeah. ​ (sneaks off) ​ ​ ​ ​
Feb
4
comment Asymptotic Behavior of Ratio of Random Variables
1/n is o(1) and thus also O(1), but (1/n)/(1/n) is not o(1). ​ ​
Jan
25
comment How do we know that an integral is unsolvable?
This is the theoretical solution. ​ (I don't know how it's done in practice.) ​ ​ ​ ​
Jan
25
comment Find the maximum value of $(12\sin x-9\sin^{2} x)$
$\sin^2(x)$ ​ is usually not equal to $\sin(x)$. ​ ​ ​ ​
Jan
21
comment What is an example of a non-zero “ring pseudo-homomorphism”?
Shoiuld $\: f(1_S) \:$ be replaced with $1_S$? $\;\;\;\;$
Jan
21
comment Prove that, if $0<y<1$, then for all $\epsilon>0$ there exists a natural numbers $n$ such that $y^{n} < \epsilon$.
Are you allowed to use infima? ​ ​
Jan
17
comment Collecting Closed Balls $B_\varepsilon(X)$ on a space $S$…
Every metric induces a topology. ​ (Highly different metrics can induce the same topology, which is why I phrased my previous sentence that way.) ​ It is "necessary ... in a topological space", but not "to define ... of an open" set. ​ ​ ​ ​
Jan
17
comment Collecting Closed Balls $B_\varepsilon(X)$ on a space $S$…
That only makes sense if S is a subspace of a particular other metric space. ​ ​
Jan
7
comment Basic understanding of quotients of “things”?
(Note that ​ ±0 = 0 .) ​ ​ ​ ​
Dec
26
awarded  Yearling
Dec
19
revised Is there any error in my solution?
shortened title and inserted line-break
Dec
10
comment Must eigenvalues be numbers?
@user2357112 : ​ That's only if there is a non-zero vector. ​ ​ ​ ​
Dec
7
comment Arc of positive planar measure
en.wikipedia.org/wiki/Osgood_curve ​ ​
Dec
6
revised Why is this set compact in $L^2(\mathbb{N})$?
improved grammar and spacing
Nov
18
comment Why is it legitimate to perform multiplication with differentials dx?
The direction you're questioning makes me curious. $\;\;\;$ How did you get $\: dy = 5dx \:$ in the first place? $\;\;\;\;\;\;\;\;$
Nov
15
reviewed Edit $T(x) = \{\frac{1}{x} \}$ invariant measure
Nov
15
revised $T(x) = \{\frac{1}{x} \}$ invariant measure
Fixed grammar and changed spacing
Nov
15
comment $T(x) = \{\frac{1}{x} \}$ invariant measure
Should $\: \left\{\frac1x \right\} \:$ be replaced with $\: \left\lfloor \frac1x \right\rfloor \;$? $\;\;\;\;$