Albert Renshaw
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 Mar 5 comment The three-coin-flip riddle It seems to me that the frogs are not MM or MF or anything but are rather "??" and once at least one identifies as male you are now left with "M?" but the "?" is still what its' always been, 50:50 male:female Mar 5 comment The three-coin-flip riddle So if I was in the forest and I heard but did not see the croak it's $2/3$, but had I turned my head a few seconds earlier and also seen which croaked all of a sudden it's $1/2$? This doesn't make much sense to me, it seems as if real world objects can behave like quantum mechanics, just by observing you change another's odds? Mar 5 comment The three-coin-flip riddle This just seems like gamblers fallacy though... @Graffitics Mar 5 comment The three-coin-flip riddle Scratch that @A.S. I remember reading about this! (Wasn't alive back then). I did think their formulas worked however, it's just when you have loss day after day after day with overhead increasing it is possible for risked wealth to go over-unity. They just weren't expecting extreme loss for that many days in a row. Mar 5 comment The three-coin-flip riddle Ok, what's LTCM? Mar 5 revised The three-coin-flip riddle added 36 characters in body Mar 5 comment The three-coin-flip riddle @Graffitics but the monty hall problem relies on a guaranteed pre-set of 2 goats and 1 car, and also the pre-knowledge (by the hose) of which doors contain which objects. Mar 5 comment The three-coin-flip riddle @A.S. +1, Sorry it's just that he is a PhD in physics so I assume I am wrong (as I did not even go to college (pursued business) haha). Just wanted to get multiple opinions with the scenario I posed. Mar 5 revised The three-coin-flip riddle added 64 characters in body Mar 5 asked The three-coin-flip riddle Feb 16 comment $z/27=x$, Digital root of the first three digits of the decimal places of x = digital root of z. Why? Very nice! Thank you. Feb 16 accepted $z/27=x$, Digital root of the first three digits of the decimal places of x = digital root of z. Why? Feb 15 comment $z/27=x$, Digital root of the first three digits of the decimal places of x = digital root of z. Why? I see what you're saying, I do have a disconnect at one point. You say that r/27 always takes the form of 111m+37k where k is the remainder of r/3 and m is r/3 minus k. How do you know that's always the case? I believe you, I just am wondering how you arrived at that haha Feb 15 comment $z/27=x$, Digital root of the first three digits of the decimal places of x = digital root of z. Why? Sorry was sleeping. Reading now. Feb 15 revised $z/27=x$, Digital root of the first three digits of the decimal places of x = digital root of z. Why? added 1 character in body; edited title Feb 15 revised $z/27=x$, Digital root of the first three digits of the decimal places of x = digital root of z. Why? added 224 characters in body Feb 15 comment $z/27=x$, Digital root of the first three digits of the decimal places of x = digital root of z. Why? Good catch! +1 —— It actually is [half] true for 27/27 because the answer is not only 1.00000 but is also 0.999999 since they are one in the same. And 9+9+9=27-->2+7=9 but yes, numbers evenly divisible by 27 are the only exception. Feb 15 asked $z/27=x$, Digital root of the first three digits of the decimal places of x = digital root of z. Why? Jan 27 comment Does the commutative property not apply when multiplying Quaternions @fleablood Thanks, now that I think about it quaternion multiplication is matrix multiplication. Since quaternions are points on a cartesian 4D hyper-field, they can be represented as vectors on [r, i, j, k]. e.g. "j" could be seen as [0,0,1,0] Jan 27 revised Does the commutative property not apply when multiplying Quaternions deleted 133 characters in body