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Mar
5
comment The three-coin-flip riddle
It seems to me that the frogs are not MM or MF or anything but are rather "??" and once at least one identifies as male you are now left with "M?" but the "?" is still what its' always been, 50:50 male:female
Mar
5
comment The three-coin-flip riddle
So if I was in the forest and I heard but did not see the croak it's $2/3$, but had I turned my head a few seconds earlier and also seen which croaked all of a sudden it's $1/2$? This doesn't make much sense to me, it seems as if real world objects can behave like quantum mechanics, just by observing you change another's odds?
Mar
5
comment The three-coin-flip riddle
This just seems like gamblers fallacy though... @Graffitics
Mar
5
comment The three-coin-flip riddle
Scratch that @A.S. I remember reading about this! (Wasn't alive back then). I did think their formulas worked however, it's just when you have loss day after day after day with overhead increasing it is possible for risked wealth to go over-unity. They just weren't expecting extreme loss for that many days in a row.
Mar
5
comment The three-coin-flip riddle
Ok, what's LTCM?
Mar
5
revised The three-coin-flip riddle
added 36 characters in body
Mar
5
comment The three-coin-flip riddle
@Graffitics but the monty hall problem relies on a guaranteed pre-set of 2 goats and 1 car, and also the pre-knowledge (by the hose) of which doors contain which objects.
Mar
5
comment The three-coin-flip riddle
@A.S. +1, Sorry it's just that he is a PhD in physics so I assume I am wrong (as I did not even go to college (pursued business) haha). Just wanted to get multiple opinions with the scenario I posed.
Mar
5
revised The three-coin-flip riddle
added 64 characters in body
Mar
5
asked The three-coin-flip riddle
Feb
16
comment $z/27=x$, Digital root of the first three digits of the decimal places of x = digital root of z. Why?
Very nice! Thank you.
Feb
16
accepted $z/27=x$, Digital root of the first three digits of the decimal places of x = digital root of z. Why?
Feb
15
comment $z/27=x$, Digital root of the first three digits of the decimal places of x = digital root of z. Why?
I see what you're saying, I do have a disconnect at one point. You say that r/27 always takes the form of 111m+37k where k is the remainder of r/3 and m is r/3 minus k. How do you know that's always the case? I believe you, I just am wondering how you arrived at that haha
Feb
15
comment $z/27=x$, Digital root of the first three digits of the decimal places of x = digital root of z. Why?
Sorry was sleeping. Reading now.
Feb
15
revised $z/27=x$, Digital root of the first three digits of the decimal places of x = digital root of z. Why?
added 1 character in body; edited title
Feb
15
revised $z/27=x$, Digital root of the first three digits of the decimal places of x = digital root of z. Why?
added 224 characters in body
Feb
15
comment $z/27=x$, Digital root of the first three digits of the decimal places of x = digital root of z. Why?
Good catch! +1 —— It actually is [half] true for 27/27 because the answer is not only 1.00000 but is also 0.999999 since they are one in the same. And 9+9+9=27-->2+7=9 but yes, numbers evenly divisible by 27 are the only exception.
Feb
15
asked $z/27=x$, Digital root of the first three digits of the decimal places of x = digital root of z. Why?
Jan
27
comment Does the commutative property not apply when multiplying Quaternions
@fleablood Thanks, now that I think about it quaternion multiplication is matrix multiplication. Since quaternions are points on a cartesian 4D hyper-field, they can be represented as vectors on [r, i, j, k]. e.g. "j" could be seen as [0,0,1,0]
Jan
27
revised Does the commutative property not apply when multiplying Quaternions
deleted 133 characters in body