KKendall
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 Apr4 awarded Popular Question Mar31 accepted Use the method of cylindrical shells to find the volume generated by rotating the region bounded… Mar31 awarded Yearling Mar31 asked Use the method of cylindrical shells to find the volume generated by rotating the region bounded… Mar31 asked Find the volume of the solid by rotating the region bounded by… Mar30 comment Find the derivative of the function $F(x) = \int_{\tan{x}}^{x^2} \frac{1}{\sqrt{2+t^4}}\,dt$. and thanks @alexqwx :) I thought the same thing. Mar30 comment Find the derivative of the function $F(x) = \int_{\tan{x}}^{x^2} \frac{1}{\sqrt{2+t^4}}\,dt$. @AndréNicolas thank you for the help. That is what I meant. I was confusing the two. Mar30 revised Find the derivative of the function $F(x) = \int_{\tan{x}}^{x^2} \frac{1}{\sqrt{2+t^4}}\,dt$. Update with help from everyone Mar30 comment Find the derivative of the function $F(x) = \int_{\tan{x}}^{x^2} \frac{1}{\sqrt{2+t^4}}\,dt$. Sorry for asking... Mar30 comment Find the derivative of the function $F(x) = \int_{\tan{x}}^{x^2} \frac{1}{\sqrt{2+t^4}}\,dt$. Yikes you guys are mean Mar30 comment Find the derivative of the function $F(x) = \int_{\tan{x}}^{x^2} \frac{1}{\sqrt{2+t^4}}\,dt$. I originally had "integrate" when that was incorrect, I edited to to read "Find the derivative". Mar30 revised Find the derivative of the function $F(x) = \int_{\tan{x}}^{x^2} \frac{1}{\sqrt{2+t^4}}\,dt$. Changed explanation of what to do. Mar30 reviewed Approve Find the derivative of the function $F(x) = \int_{\tan{x}}^{x^2} \frac{1}{\sqrt{2+t^4}}\,dt$. Mar30 asked Find the derivative of the function $F(x) = \int_{\tan{x}}^{x^2} \frac{1}{\sqrt{2+t^4}}\,dt$. Mar18 awarded Popular Question Sep26 awarded Popular Question Sep24 awarded Autobiographer Aug6 comment find the area of the shaded region $x=y^2-1, y=1, x=\sqrt y$ Ahh, I think I understand. The integral is from 0 to 1, the 1 comes from y=1? Aug6 comment find the area of the shaded region $x=y^2-1, y=1, x=\sqrt y$ Thank you! Using y seems easier, didn't realize I could do it like that. It seems like the y=1 just disappears, could you explain what happens with that for me? Aug6 comment find the area of the shaded region $x=y^2-1, y=1, x=\sqrt y$ I messed up... I forgot to get the antiderivative, I just plugged in -1 and 1 to the original equation...