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14h
comment Finding bivariate probability mass function (by counting?)
Many thanks! This clarifies things perfectly!
1d
comment Finding bivariate probability mass function (by counting?)
Many thanks for this great answer! I am still having trouble seeing how this result was derived so let me ask an additional question. Suppose we roll $3$ dice (instead of $d$) and we are interested in $P(X=4, Y=3)$. Would it be too much to ask of you to list the outcomes (i.e. the triples of dice values) that we are counting to find this probability? For example we want the outcome $431$ and $432$. Which others do we need?
1d
comment Finding bivariate probability mass function (by counting?)
I was hesitant myself when writing that particular segment, but since I am not a native speaker of English, mistakes are inevitable. Thanks for pointing that out (and correcting it)!
1d
comment A priori probability in Bayesian inference problem
Thanks for your help, and especially for providing the numerical implementation! It really clarified things!
1d
comment A priori probability in Bayesian inference problem
Thank you very much for the detailed answer!
Jan
21
comment Conditional expectation in Poisson point process
Thanks very much for the very detailed answer!
Jan
21
comment Sum of transformations of continuous uniform random variable
Much obliged. Thanks especially for taking the time to go through the measure-theoretic details of the argument!
Oct
15
comment Convergence of Binet's formula expression for Fibonacci
Sorry! Corrected!
May
9
comment The composition of a nowhere-differentiable function with a differentiable function.
Probably not. That was the first thing that came to my mind but this problem is way before power series are introduced. I am starting to wonder whether this is a badly worded problem...
May
8
comment The composition of a nowhere-differentiable function with a differentiable function.
This was not clear to me either. I have copied the exercise as it appears on the book and I tried to assume it was nowhere differentiable.
May
8
comment The composition of a nowhere-differentiable function with a differentiable function.
I want to assume that $f$ is nowhere differentiable, otherwise the problem is pretty easy to handle.
Oct
6
comment Is this $\beta$-reduction well defined?
The question is whether it is possible to operate as it is.
Jul
4
comment A step in the proof of the Riemann Mapping Theorem
Are we considering the graph of $sin(1/x)$ as a subset of $\overline{\Bbb C}$?
Apr
19
comment Abelian group admitting a surjective homomorphism onto an infinite cyclic group
I just realised my stupid mistake! Just one more thing. How can I show that any element of $G$ is expressible as a product of two elements, the first of which is from $\ker(f)$ and the second from $im(g)$?
Apr
19
comment Studying the action of $GL(V)$ on the vector space $V$
Thank you very much! It is all clear now!
Apr
19
comment Abelian group admitting a surjective homomorphism onto an infinite cyclic group
I have tried to show that $\ker(g)$ is trivial, but I am failing to do so. My problem is that the $x$ you chose above might have finite order so you would have $nx=0$ with $n \neq 0$ thus the kernel will not be trivial. I cannot find a method to by-pass this problem.
Apr
16
comment Abelian group admitting a surjective homomorphism onto an infinite cyclic group
I am so very sorry for not understanding this immediately. Here is my point of confusion. I cannot see how $G = \ker(f) \times im(g) \implies G \cong \ker(f) \times \Bbb Z$, since $im(g) \subset G$ so you would get $G \cong \ker(f) \times im(g) \subset \ker(f) \times G$
Apr
12
comment Generalised eigenvalue is eigenvalue if it is in the field
Thank you very much for your help, Branimir!
Apr
12
comment Generalised eigenvalue is eigenvalue if it is in the field
I see my mistake! Thank you very much for pointing this out!
Mar
24
comment Imposing the topology of open rays in $\Bbb R$
Dear Brian, I would like to ask your permission to integrate your suggestions and hints into a complete answer in my original post. May I do so?