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 Yearling
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Jan
11
awarded  Yearling
Dec
16
awarded  Popular Question
Jul
2
awarded  Curious
Jan
30
asked Is continuum $ 2^{\mathbb{R}}$?
Jan
11
awarded  Yearling
Jan
6
accepted continuous function $h(x)=\sup\{f(t)\colon t\le x\}$
Jan
6
comment continuous function $h(x)=\sup\{f(t)\colon t\le x\}$
why $h(y) \le h(x)+\delta.$
Jan
6
comment continuous function $h(x)=\sup\{f(t)\colon t\le x\}$
I have no idea, maybe some hint?
Jan
6
asked continuous function $h(x)=\sup\{f(t)\colon t\le x\}$
Sep
6
accepted Series expansion at $x=0$ of $\frac{3x}{1+x^2 + x^4}$
Sep
6
asked Series expansion at $x=0$ of $\frac{3x}{1+x^2 + x^4}$
Sep
3
accepted Explicit formula for a recursive series?
Sep
3
accepted determinant $s=n+1$
Aug
29
revised Explicit formula for a recursive series?
added 34 characters in body
Aug
29
asked Explicit formula for a recursive series?
Aug
27
asked Length of function
Aug
27
accepted Numbers of solutions $e^x=-x^2+2x+5 $
Aug
27
asked Numbers of solutions $e^x=-x^2+2x+5 $
Aug
27
accepted convergence of the integral (with parameter)
Aug
27
comment convergence of the integral (with parameter)
ok, i know how to use your hint, but now need to show that $\int_0^\infty \frac{dx}{(x^2-x)^{2c}}$ is converges when $ 1/4<c<1/3$