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visits member for 1 year, 3 months
seen Feb 2 at 21:40

Jan
30
asked Is continuum $ 2^{\mathbb{R}}$?
Jan
11
awarded  Yearling
Jan
6
accepted continuous function $h(x)=\sup\{f(t)\colon t\le x\}$
Jan
6
comment continuous function $h(x)=\sup\{f(t)\colon t\le x\}$
why $h(y) \le h(x)+\delta.$
Jan
6
comment continuous function $h(x)=\sup\{f(t)\colon t\le x\}$
I have no idea, maybe some hint?
Jan
6
asked continuous function $h(x)=\sup\{f(t)\colon t\le x\}$
Sep
6
accepted Series expansion at $x=0$ of $\frac{3x}{1+x^2 + x^4}$
Sep
6
asked Series expansion at $x=0$ of $\frac{3x}{1+x^2 + x^4}$
Sep
3
accepted Explicit formula for a recursive series?
Sep
3
accepted determinant $s=n+1$
Aug
29
revised Explicit formula for a recursive series?
added 34 characters in body
Aug
29
asked Explicit formula for a recursive series?
Aug
27
asked Length of function
Aug
27
accepted Numbers of solutions $e^x=-x^2+2x+5 $
Aug
27
asked Numbers of solutions $e^x=-x^2+2x+5 $
Aug
27
accepted convergence of the integral (with parameter)
Aug
27
comment convergence of the integral (with parameter)
ok, i know how to use your hint, but now need to show that $\int_0^\infty \frac{dx}{(x^2-x)^{2c}}$ is converges when $ 1/4<c<1/3$
Aug
27
comment convergence of the integral (with parameter)
still dont know what to do. What integral convergence tests to use?
Aug
27
comment convergence of the integral (with parameter)
Yes, c is constant parameter $\in \mathbb{R}$
Aug
27
asked convergence of the integral (with parameter)