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 Inquisitive
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Mar
24
awarded  Inquisitive
Mar
1
comment Finding the Basis of the Subspace U
Note that last vector is sum of first three, i.e, given set of vector are linearly dependent.
Feb
29
answered Petersen graph is tripartite
Feb
29
revised Bases for $\mathbb{F}_2$ and for $M_{2\times2}(\mathbb{F})$
formatting
Feb
29
suggested approved edit on Bases for $\mathbb{F}_2$ and for $M_{2\times2}(\mathbb{F})$
Feb
26
revised MLE for a uniform distribution
Improved formatting
Feb
26
suggested approved edit on MLE for a uniform distribution
Feb
26
awarded  Custodian
Feb
26
reviewed No Action Needed Showing that an element generates the kernel
Feb
24
answered Column Space vs Span and minimum size of a set of vectors to guarantee a vector is in span?
Feb
22
asked Trapezoid graph representation
Feb
15
accepted Is it true that sequence of non negative reals converging to one can not have initial term zero
Feb
15
comment Is it true that sequence of non negative reals converging to one can not have initial term zero
but limit is zero.
Feb
15
revised Is it true that sequence of non negative reals converging to one can not have initial term zero
deleted 1 character in body; edited title
Feb
15
comment Is it true that sequence of non negative reals converging to one can not have initial term zero
Sorry I missed [0,1] and limit one
Feb
15
revised Is it true that sequence of non negative reals converging to one can not have initial term zero
edited body
Feb
15
asked Is it true that sequence of non negative reals converging to one can not have initial term zero
Jan
12
comment Given a graph $G = (V, E)$, prove $e \leq \frac{n(n-1)}{2}$ for all $n$
Induction hypothesis: If $G$ has $k$ vertices then it has at most $k(k-1)/2$ edges. Suppose if we add another vertex then it can create at most $k$ new edges. So the total number of edges in $k+1$ vertex graph is at most $k+ k(k-1)/2=k(k+1)/2$
Jan
10
awarded  Yearling
Jan
10
accepted Interval order dimension of a Poset