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 Mar 11 revised Evaluating a series practically edited tags Mar 11 comment Evaluating a series practically @SSS That solves the odd iterating issue, thank you. Mar 11 comment Evaluating a series practically @Alexis You are right - I have corrected my post. Mar 11 revised Evaluating a series practically alternate form Mar 11 asked Evaluating a series practically Oct 22 awarded Notable Question Sep 9 awarded Popular Question Sep 1 awarded Popular Question Jan 8 comment Iterated Function System Definition @Dan Christensen Understood. However, if the set were to fulfill the requirements of the Cantor set, would that be $f_3(x)$? Jan 8 comment Iterated Function System Definition I do realize that the functions could be completely arbitrary, but I was interested in distinguishing how IFSs are used with fractals. Jan 8 accepted Iterated Function System Definition Jan 8 comment Iterated Function System Definition Oh, I see. If it were to be a fractal, however, would that be the case? Jan 8 comment Iterated Function System Definition You would have to provide a starting function though, correct? In other words, it would always be $f_1(x)$. Jan 8 comment Iterated Function System Definition The only implicit assumption is that $f(x)$ is somehow defined and that, as you said, each one maps $X$ to itself? Jan 8 comment Iterated Function System Definition Would the third function be: $f_3(x) = \frac{x}{3} + \left( \frac{2}{3} + \frac{\frac{x}{3} + \frac{2}{3}}{3}\right)$? Jan 8 asked Iterated Function System Definition Feb 27 comment Leibniz Rule Check: $h(x)=\int_{0}^{2x - 1} f(t) dt$ That makes sense - so at $x = 2.5$ there is a relative maximum. Feb 27 accepted Leibniz Rule Check: $h(x)=\int_{0}^{2x - 1} f(t) dt$ Feb 27 revised Leibniz Rule Check: $h(x)=\int_{0}^{2x - 1} f(t) dt$ edited body Feb 27 comment Leibniz Rule Check: $h(x)=\int_{0}^{2x - 1} f(t) dt$ Sorry for the crummy picture!