175 reputation
1619
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location Stockholm, Sweden
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visits member for 3 years, 11 months
seen yesterday

Enthusiastic about computer systems for business and technical applications.


1d
accepted Is there a good way to solve for z the equation $e^{i\pi} = e^{z\ln2} + e^{z\ln3}$?
1d
awarded  Nice Question
1d
revised Is there a good way to solve for z the equation $e^{i\pi} = e^{z\ln2} + e^{z\ln3}$?
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1d
comment Is there a good way to solve for z the equation $e^{i\pi} = e^{z\ln2} + e^{z\ln3}$?
Can you please elaborate how we make it two equations?
1d
revised Is there a good way to solve for z the equation $e^{i\pi} = e^{z\ln2} + e^{z\ln3}$?
added 15 characters in body
1d
revised Is there a good way to solve for z the equation $e^{i\pi} = e^{z\ln2} + e^{z\ln3}$?
added 68 characters in body
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comment Is there a good way to solve for z the equation $e^{i\pi} = e^{z\ln2} + e^{z\ln3}$?
Thanks. I'm trying to learn how to solve equations like these. Interesting it was not trivial.
1d
asked Is there a good way to solve for z the equation $e^{i\pi} = e^{z\ln2} + e^{z\ln3}$?
Dec
18
accepted How can I prove that the zeroes of $f(z)=1+1/2^z$ have no real part?
Dec
18
revised How can I prove that the zeroes of $f(z)=1+1/2^z$ have no real part?
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Dec
18
revised How can I prove that the zeroes of $f(z)=1+1/2^z$ have no real part?
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Dec
18
asked How can I prove that the zeroes of $f(z)=1+1/2^z$ have no real part?
Dec
11
awarded  Inquisitive
Dec
9
awarded  Benefactor
Dec
5
awarded  Nice Question
Dec
4
accepted Is this expression true and legal?
Oct
15
accepted Are 2 dependent probabilities always disjunct?
Oct
14
revised Are 2 dependent probabilities always disjunct?
deleted 1 character in body
Oct
14
awarded  Popular Question
Oct
13
asked Are 2 dependent probabilities always disjunct?