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  • 233 votes cast
Dec
21
awarded  Caucus
Jul
2
awarded  Curious
Oct
1
accepted Can the measurement matrix used for compressive sensing be a sparse matrix?
Sep
30
accepted Starting with $\frac{-1}{1}=\frac{1}{-1}$ and taking square root: proves $1=-1$
Sep
30
asked Can the measurement matrix used for compressive sensing be a sparse matrix?
Sep
12
accepted Handshaking with no crossovers in minimum number of rounds: has this problem been studied?
Aug
10
comment Starting with $\frac{-1}{1}=\frac{1}{-1}$ and taking square root: proves $1=-1$
But in this example, $e$, the base of the natural logarithm, is positive: $e^{z} \overset{!}{=} (e^{2\pi i})^{z/2\pi i} = 1^{z/2\pi i} = 1$ for all $z$. Is this an exception to the rule?
Aug
8
comment Starting with $\frac{-1}{1}=\frac{1}{-1}$ and taking square root: proves $1=-1$
So is it always safe to distribute the root over products and quotients if ["the number insider the root is positive" $\vee$ "the root is odd"]? Is that the rule?
Aug
7
comment Starting with $\frac{-1}{1}=\frac{1}{-1}$ and taking square root: proves $1=-1$
@ZevChonoles : The first question yes. But not the second question.
Aug
7
comment Starting with $\frac{-1}{1}=\frac{1}{-1}$ and taking square root: proves $1=-1$
Can you elaborate on why is this a problem?
Aug
7
comment Starting with $\frac{-1}{1}=\frac{1}{-1}$ and taking square root: proves $1=-1$
Related: math.stackexchange.com/questions/445585/… .
Aug
7
asked Starting with $\frac{-1}{1}=\frac{1}{-1}$ and taking square root: proves $1=-1$
Jun
30
accepted Proving that $\Pr[|X| > T\sqrt{n}/2] \geq \Pr[|X-\mathbb EX| < T\sqrt{n}/2]$
Jun
30
comment Proving that $\Pr[|X| > T\sqrt{n}/2] \geq \Pr[|X-\mathbb EX| < T\sqrt{n}/2]$
Yes. But isn't by using the triangle inequality we have: $|X-\mathbb EX+\mathbb EX|\leqslant|X-\mathbb EX|+|\mathbb EX|$? Where did the minus sign in $-|X-\mathbb EX|$ come from?
Jun
30
comment Proving that $\Pr[|X| > T\sqrt{n}/2] \geq \Pr[|X-\mathbb EX| < T\sqrt{n}/2]$
Could you kindly elaborate the first inequality? I don't seem to be able to know how it was deduced.
Jun
30
asked Proving that $\Pr[|X| > T\sqrt{n}/2] \geq \Pr[|X-\mathbb EX| < T\sqrt{n}/2]$
Jun
26
comment Does this probability distribution have a name?
Hey, thanks for the answer. Would you kindly provide some explanation of how you reached this conclusion?
Mar
5
accepted The smallest normal set containing a subset $X$, what is a “normal set”?
Feb
22
awarded  Announcer
Jun
8
awarded  Constituent