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Mar
30
revised Proof of the diagonalization of the probability matrix of the sum of two binomial distributions
edited tags
Mar
30
revised Proof of the diagonalization of the probability matrix of the sum of two binomial distributions
partial progress
Mar
21
awarded  Tumbleweed
Mar
14
asked Proof of the diagonalization of the probability matrix of the sum of two binomial distributions
Feb
26
awarded  Excavator
Feb
26
revised Lower bounds for inner product $x^\top y$
Changed >= to \geq
Feb
26
suggested approved edit on Lower bounds for inner product $x^\top y$
Feb
24
comment Addition of two Binomial Distribution
It has a special name: Poisson Binomial distribution.
Feb
24
answered Addition of two Binomial Distribution
Dec
19
comment Norm of a Matrix-vector product
What is that inequality called?
Dec
21
awarded  Caucus
Jul
2
awarded  Curious
Oct
1
accepted Can the measurement matrix used for compressive sensing be a sparse matrix?
Sep
30
accepted Starting with $\frac{-1}{1}=\frac{1}{-1}$ and taking square root: proves $1=-1$
Sep
30
asked Can the measurement matrix used for compressive sensing be a sparse matrix?
Sep
12
accepted Handshaking with no crossovers in minimum number of rounds: has this problem been studied?
Aug
10
comment Starting with $\frac{-1}{1}=\frac{1}{-1}$ and taking square root: proves $1=-1$
But in this example, $e$, the base of the natural logarithm, is positive: $e^{z} \overset{!}{=} (e^{2\pi i})^{z/2\pi i} = 1^{z/2\pi i} = 1$ for all $z$. Is this an exception to the rule?
Aug
8
comment Starting with $\frac{-1}{1}=\frac{1}{-1}$ and taking square root: proves $1=-1$
So is it always safe to distribute the root over products and quotients if ["the number insider the root is positive" $\vee$ "the root is odd"]? Is that the rule?
Aug
7
comment Starting with $\frac{-1}{1}=\frac{1}{-1}$ and taking square root: proves $1=-1$
@ZevChonoles : The first question yes. But not the second question.
Aug
7
comment Starting with $\frac{-1}{1}=\frac{1}{-1}$ and taking square root: proves $1=-1$
Can you elaborate on why is this a problem?