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 Jun2 asked What is a bounded discrete random variable Apr25 awarded Popular Question Apr14 awarded Popular Question Apr13 comment Case C: Euler's equation in Simmon's textbook I've adjusted my work above to reflect what I learned from your comment. Am I understanding this properly? Apr13 revised Case C: Euler's equation in Simmon's textbook added 1200 characters in body Apr12 asked Case C: Euler's equation in Simmon's textbook Mar26 asked Classification type of equilibrium point Jan5 awarded Yearling Nov24 asked Why is SSE called unexplained variation Aug15 asked Examples of Lebesgue dominated convergence theorem Jul13 comment Folland, Chapter 1 Problem 17 Eric, nope, you have it incorrect. It might be because we're using different letters and it's getting you confused. Here is the definition, direct from Folland: If $\mu^*$ is an outer measure on $X$, a set $A\subset X$ is called $\mu^*$-measurable if $\mu^*(E)=\mu^*(E\cap A)+\mu^*(E\cap A^C)$ for all $E\subset X$. Now if I change my letters it would read: A set $E$ is called $\mu^*$-measurable if $\mu^*(A)=\mu^*(A\cap E)+\mu^*(A\cap E^C)$ for all $A\subset X$. Hope this helps. Jul13 comment Folland, Chapter 1 Problem 17 $B$ is the union of a countable number of disjoint $\mu^*$-measurable sets, so $B$ is measurable, meaning $\mu^*(E)=\mu^*(E\cap B)+\mu^*(E\cap B^C)$ for any $E\subset X$. Jul13 asked Folland, Chapter 1 Problem 17 Jul12 answered Folland Proposition 1.13 Real Analysis, Second Edition Jul12 revised Folland Proposition 1.13 Real Analysis, Second Edition edited title Jul12 asked Folland Proposition 1.13 Real Analysis, Second Edition Jul10 asked Holder's inequality and an infinite series question Jul9 comment Constructing a complete measure space In your latest proof, why is $\mu(U\cup G)=0$? Jul9 comment Constructing a complete measure space Nope, still a problem. You have $E=\phi\cup E$. To show that this is an element in $B_0$, you have to show that $\phi\in B$ (which is true) and $E\in B_0$, which hasn't been shown. $F\in B_0$ and $E\subset F$ does not necessarily mean that $E\in B$. Jul9 comment Constructing a complete measure space Using these characters and the hypotheses set up, I believe what is needed is to prove that $E\in B_0$, which I don't see that this is saying.