37 reputation
4
bio website achiralsarkar.wordpress.com
location India
age 19
visits member for 4 months
seen Jan 31 at 6:53
stats profile views 27

I am undergraduate student majoring in Physics.I like to see myself as an autodidact who is also a self-deluding dilettante.

Apart from physics, my interests include mathematics and computer science. I am a computer enthusiast and I enjoy science fiction and computer games. I also dabble in English literature, politics and philosophy.

I am a free thinker and advocate a naturalist world view.


Jan
29
accepted Is the Dirac Delta “Function” really a function?
Jan
28
accepted Proof of Cauchy–Schwarz inequality
Jan
28
awarded  Supporter
Jan
28
comment Proof of Cauchy–Schwarz inequality
@Andre Nicolas: I understand it now. If you want you could elaborate your first comment and add it to the answer.
Jan
28
comment Proof of Cauchy–Schwarz inequality
@valtron : No, I was talking about the roots of the quadratic equation.....for the unknown x can never be real and distinct, but must be imaginary,unless a and b are proportional.
Jan
28
comment Proof of Cauchy–Schwarz inequality
I am familiar with the proof give in Steele's book. But I am trying to understand this particular proof (i.e., the one form Hilbert and Courant.)
Jan
28
comment Proof of Cauchy–Schwarz inequality
Yes, I know that! I can't figure out why are they avoiding the real roots and from the language that is being employed by the authors, does it not mean that "The roots can not be real unless a and b are proportional" And just before that they have stated a and b must be proportional. Sorry, but I am confused.
Jan
28
asked Proof of Cauchy–Schwarz inequality
Jan
24
awarded  Student
Jan
24
asked Is the Dirac Delta “Function” really a function?
Jan
4
awarded  Scholar
Jan
4
accepted Dirichlet Conditions and Fourier Analysis.
Jan
4
comment Dirichlet Conditions and Fourier Analysis.
I also came across the fact that arcsin x has a convergent Fourier series but does not satisfy the Dirichlet conditions. The conditions are "not necessary" because no one proved a theorem that if the Fourier series of a function f(x) converge pointwise then the function satisfies the Dirichlet conditions. makes sense!
Jan
3
answered Checking discontinuity
Jan
3
comment Dirichlet Conditions and Fourier Analysis.
Yes, that is why we can not express it in terms of Fourier series. It has an infinite discontinuity at pi/2 and hence can not be expanded in the interval -pi to pi. The question is why are the Dirichlet conditions deemed 'NOT NECESSARY'.
Jan
3
asked Dirichlet Conditions and Fourier Analysis.
Jan
2
awarded  Autobiographer