| bio | website | achiralsarkar.wordpress.com |
|---|---|---|
| location | India | |
| age | 19 | |
| visits | member for | 4 months |
| seen | Jan 31 at 6:53 | |
| stats | profile views | 27 |
I am undergraduate student majoring in Physics.I like to see myself as an autodidact who is also a self-deluding dilettante.
Apart from physics, my interests include mathematics and computer science. I am a computer enthusiast and I enjoy science fiction and computer games. I also dabble in English literature, politics and philosophy.
I am a free thinker and advocate a naturalist world view.
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Jan 29 |
accepted | Is the Dirac Delta “Function” really a function? |
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Jan 28 |
accepted | Proof of Cauchy–Schwarz inequality |
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Jan 28 |
awarded | Supporter |
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Jan 28 |
comment |
Proof of Cauchy–Schwarz inequality @Andre Nicolas: I understand it now. If you want you could elaborate your first comment and add it to the answer. |
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Jan 28 |
comment |
Proof of Cauchy–Schwarz inequality @valtron : No, I was talking about the roots of the quadratic equation.....for the unknown x can never be real and distinct, but must be imaginary,unless a and b are proportional. |
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Jan 28 |
comment |
Proof of Cauchy–Schwarz inequality I am familiar with the proof give in Steele's book. But I am trying to understand this particular proof (i.e., the one form Hilbert and Courant.) |
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Jan 28 |
comment |
Proof of Cauchy–Schwarz inequality Yes, I know that! I can't figure out why are they avoiding the real roots and from the language that is being employed by the authors, does it not mean that "The roots can not be real unless a and b are proportional" And just before that they have stated a and b must be proportional. Sorry, but I am confused. |
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Jan 28 |
asked | Proof of Cauchy–Schwarz inequality |
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Jan 24 |
awarded | Student |
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Jan 24 |
asked | Is the Dirac Delta “Function” really a function? |
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Jan 4 |
awarded | Scholar |
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Jan 4 |
accepted | Dirichlet Conditions and Fourier Analysis. |
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Jan 4 |
comment |
Dirichlet Conditions and Fourier Analysis. I also came across the fact that arcsin x has a convergent Fourier series but does not satisfy the Dirichlet conditions. The conditions are "not necessary" because no one proved a theorem that if the Fourier series of a function f(x) converge pointwise then the function satisfies the Dirichlet conditions. makes sense! |
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Jan 3 |
answered | Checking discontinuity |
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Jan 3 |
comment |
Dirichlet Conditions and Fourier Analysis. Yes, that is why we can not express it in terms of Fourier series. It has an infinite discontinuity at pi/2 and hence can not be expanded in the interval -pi to pi. The question is why are the Dirichlet conditions deemed 'NOT NECESSARY'. |
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Jan 3 |
asked | Dirichlet Conditions and Fourier Analysis. |
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Jan 2 |
awarded | Autobiographer |

