Reputation
Top tag
Next privilege 250 Rep.
View close votes
Badges
2 12
Impact
~6k people reached

  • 0 posts edited
  • 0 helpful flags
  • 67 votes cast
Apr
22
revised Separable and purely inseparable extensions over fields of characteristic $p$
added 99 characters in body; edited tags
Apr
20
asked Separable and purely inseparable extensions over fields of characteristic $p$
Apr
20
comment Order of a map $\Bbb F_{p^n}\to \Bbb F_{p^n}$which maps $x$ to $x^{p} -x$
My question is answered at math.stackexchange.com/questions/1384817/…. Plz close this post as it duplicated.
Apr
20
revised Order of a map $\Bbb F_{p^n}\to \Bbb F_{p^n}$which maps $x$ to $x^{p} -x$
added 4 characters in body
Apr
19
asked Order of a map $\Bbb F_{p^n}\to \Bbb F_{p^n}$which maps $x$ to $x^{p} -x$
Apr
14
comment char$(K)=0$ then $K(x^{2}) \cap K(x^{2}-x)=K$
Yes, you can close this if necessary. Actually I was searching for answers on our site but I couldn't find any. Jyrki's suggestion is really helpful.
Apr
14
asked char$(K)=0$ then $K(x^{2}) \cap K(x^{2}-x)=K$
Apr
13
comment Definitions of length function on a Weyl group
Thanks for the answer. That is helpful.
Apr
13
accepted Definitions of length function on a Weyl group
Apr
13
comment If $K \subset \mathbb{Q}(\sqrt[p]{2},\sqrt[q]{2})$ and $[K : \mathbb{Q}]=p$ then $K= \mathbb{Q}(\sqrt[p]{2})$
Great answer! You did use the assumption that $p<q$ here. Please take a look at my edited post. Will the problem be true if $p,q$ are just distinct primes?
Apr
13
accepted If $K \subset \mathbb{Q}(\sqrt[p]{2},\sqrt[q]{2})$ and $[K : \mathbb{Q}]=p$ then $K= \mathbb{Q}(\sqrt[p]{2})$
Apr
13
revised If $K \subset \mathbb{Q}(\sqrt[p]{2},\sqrt[q]{2})$ and $[K : \mathbb{Q}]=p$ then $K= \mathbb{Q}(\sqrt[p]{2})$
added 711 characters in body
Apr
13
revised If $K \subset \mathbb{Q}(\sqrt[p]{2},\sqrt[q]{2})$ and $[K : \mathbb{Q}]=p$ then $K= \mathbb{Q}(\sqrt[p]{2})$
[Edit removed during grace period]
Apr
13
asked If $K \subset \mathbb{Q}(\sqrt[p]{2},\sqrt[q]{2})$ and $[K : \mathbb{Q}]=p$ then $K= \mathbb{Q}(\sqrt[p]{2})$
Mar
16
comment Semilocal commutative ring with two or three maximal ideals
@JohnBrevik How can you prove that there is no maximal ideals other than $(2)$ and $(3)$?
Dec
2
awarded  Notable Question
Nov
6
comment The longest word in Weyl group and positive roots.
I was asking a similar question in here math.stackexchange.com/questions/1513075/…. If you have time plz take a look.
Nov
6
comment The longest word in Weyl group and positive roots.
Yes, you're correct by saying that I'm mentioning "height" of positive roots. My recently question is exact what you say if given reduced expression $w=s_{1}s_{2}\cdots s_{r}$ ($s_{i}$ simple reflection w.r.t simple $\alpha_i$) then $\beta_i:=s_rs_{r-1}\ldots s_{i+1}(\alpha_i), \beta_r:=\alpha_r$ are positive roots sent negative by $w$. I wanted to know that can we order them as $\beta_r<\beta_{r-1}<\ldots<\beta_1$ with $<$ I mean the order I defined previously?
Nov
6
comment The longest word in Weyl group and positive roots.
@HughDenoncourt Thank you. In your first comment, by $"<"$ you meant "reflection ordering" that defined in Bjorner and Brenti's textbook? Isn't it the usual lexicographic order that $\alpha \le \beta \iff \beta -\alpha$ is a linear combination of simple roots with non-negative coefficients?
Nov
5
comment The longest word in Weyl group and positive roots.
@HughDenoncourt Can you give me the references of ordering roots in your first comment?