| bio | website | maths.adelaide.edu.au/… |
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| location | Adelaide, Australia | |
| age | ||
| visits | member for | 4 months |
| seen | 22 hours ago | |
| stats | profile views | 11 |
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Jan 15 |
awarded | Supporter |
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Jan 7 |
revised |
Non linear transformation satisfying $T(x+y)=T(x)+T(y)$ Previous comment on automorphisms of $\mathbb{C}$ removed as not really relevant. |
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Jan 6 |
answered | Non linear transformation satisfying $T(x+y)=T(x)+T(y)$ |
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Jan 3 |
comment |
Short Five Lemma for Fibrations OK I understand. Thanks. In that case I think you can do $E = E' = \mathbb{R}^2$, $B = B' = \mathbb{R}$ and $F = F' = \mathbb{R}$ with the projections to $B$ being the projection on the first factor and the basepoint being $1$. Define $E \to E'$ to be $(x, y) \mapsto (x, xy)$. This is identity map on the fibre and the base but not invertible. |
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Jan 1 |
answered | Do people study $\mathbb{R}^{3}$ with copies of complex planes? |
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Jan 1 |
awarded | Teacher |
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Jan 1 |
awarded | Editor |
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Jan 1 |
revised |
Short Five Lemma for Fibrations added 105 characters in body |
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Jan 1 |
answered | Short Five Lemma for Fibrations |