Ark-kun
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 Jan 28 asked A function basis for unimodal functions. Jan 4 awarded Nice Answer Sep 30 awarded Excavator Sep 30 comment Generalized chi distribution Nevermind. Found the answer here: en.wikipedia.org/wiki/Rice_distribution#Moments Sep 30 comment Generalized chi distribution @RossB. There are very few mentions of the Noncentral Chi Distribution on the Internet. I have a problem understanding the formulas in the Wikipedia article you've linked. The formula for the mean uses the "generalized Laguerre polynomial", but its n parameter is 1/2 (L^(k/2-1)_1/2), while the linked article only deals with integer values. Can you, please, tell me how to calculate the mean of the noncentral chi distribution? Sep 29 comment length of Gaussian Random Vector AFAIK, the variables also need to be zero-centered to produce the Rayleigh distribution. Jul 20 awarded Tumbleweed Jul 13 answered Kalman filter for acceleremoter and gyro May 16 awarded Teacher May 16 answered Interesting “real life” applications of serious theorems Apr 20 comment An “additive” cryptographic hash-function that allows calculating the hash of some data from the hashes of the parts of that data. What do you think about matrix multiplication or some form of concatenation+hash (cannot think a proper function right now)? Apr 20 awarded Editor Apr 20 revised An “additive” cryptographic hash-function that allows calculating the hash of some data from the hashes of the parts of that data. added 108 characters in body Apr 20 comment An “additive” cryptographic hash-function that allows calculating the hash of some data from the hashes of the parts of that data. Well, the $N^3$ (the size of the combination operator table) can be quite big for 1024-bit hashes. But I guess, some forms of rainbow tables could make brute-forcing faster. I wanted to use such hash for a version-control system to allow addressing parts of files. Apr 20 comment An “additive” cryptographic hash-function that allows calculating the hash of some data from the hashes of the parts of that data. Why would that allow it? Suppose $h(d) = md5(md5(d[0..n/2]),md5(d[n/2+1..n]))$ $hh(h1, h2) = md5(h1, h2)$. How would that compromise the security? Apr 20 asked An “additive” cryptographic hash-function that allows calculating the hash of some data from the hashes of the parts of that data. Feb 16 awarded Student Feb 15 asked Estimating the likelihood of independence of two discrete variables using the co-occurrence count matrix. Dec 31 awarded Supporter