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 Nov 7 awarded Custodian Nov 7 reviewed Approve Why does $e$ seem to be an intuitive number? Nov 7 comment Why does $e$ seem to be an intuitive number? Umm, what does the root of 10 have to do with logarithms? Nov 7 asked Why does $e$ seem to be an intuitive number? Nov 5 comment Is 10 closer to infinity than 1? @LarsH: No, just that most languages have less shitty clauses for comparisons. In Japanese the equivalent would translate as "WRT infinity, is 1 close or 10 close". Nov 4 comment Is 10 closer to infinity than 1? @LarsH: English just sucks. Move along and use Lojban, or just almost any other language on the Earth that does not have two ways to parse almost all sentences. Nov 3 awarded Popular Question Nov 2 awarded Popular Question Oct 29 comment Completely baffled by this question involving putting matrices in matrices Ahh thanks. I was trying to concoct $R$ using multiplications and sums of things involving $P$ and $Q$... Also, is there some trick to intuitively "getting" matrix multiplication? Like, I can calculate it, but I can never eyeball even a very high-level picture of what happens to various properties when you multiply two matrices. Oct 29 accepted Completely baffled by this question involving putting matrices in matrices Oct 29 comment Completely baffled by this question involving putting matrices in matrices C is $m\times n$. Oct 29 asked Completely baffled by this question involving putting matrices in matrices Oct 10 accepted Having trouble understanding this proposition from my textbook. Oct 5 comment Having trouble understanding this proposition from my textbook. But can't $\vec{y}$ be of the wrong dimension to multiply by $A$? After all, it is formed with $A_B$, which has different dimensions from $A$. Oct 5 asked Having trouble understanding this proposition from my textbook. Oct 1 accepted Is matrix multiplication by an invertible matrix one-to-one and onto? Oct 1 comment Is matrix multiplication by an invertible matrix one-to-one and onto? What about $f(X)=XA$? Oct 1 comment Is matrix multiplication by an invertible matrix one-to-one and onto? Yes, but how about the "inverse" multiplication? Also, $X$ is a matrix, not a vector. Oct 1 asked Is matrix multiplication by an invertible matrix one-to-one and onto? Sep 18 comment Confusing DE concept question Define "reduced".