159 reputation
218
bio website tudelft.nl
location Delft, Netherlands
age 27
visits member for 1 year, 8 months
seen 45 mins ago

Aug
2
comment Determine the target weight so that no more than 5% of boxes with normal weight distribution contain less than 500 g
@loading.... & Shahar - Wolfram can't do the definite integral, because of some $0/0$ arguments, but you can find the indefinite integral as you can see here and fill in the boundaries in an intelligent way yourself
Aug
2
accepted Area of the polygon formed by cutting a cube with a plane
Aug
2
comment Area of the polygon formed by cutting a cube with a plane
Great, thank you!
Aug
2
comment Area of the polygon formed by cutting a cube with a plane
Terrific explanation! Quick question: is there an easy way to deal with the case for which $m_i=0$ occurs? Or should I just compute the limit using l'hopital's rule?
Aug
2
comment Area of the polygon formed by cutting a cube with a plane
@CalvinLin I will certainly try that, thanks! I do wonder whether that easily generalizes to polygons with a different number of vertices (due to a different cut of the box)
Aug
2
comment Area of the polygon formed by cutting a cube with a plane
@StephenNand-Lal Good point, completely forgot the word for it. Yes I do, edited it.
Aug
2
asked Area of the polygon formed by cutting a cube with a plane
Jul
26
awarded  Altruist
Jul
20
awarded  Investor
Jul
2
awarded  Curious
May
9
accepted Integration and differentiation of an approximation to a function - order of approximation
May
8
comment Integration and differentiation of an approximation to a function - order of approximation
So indeed the order of the approximation changes with integration/differentation?! Interesting, I wasn't expecting that!
May
8
asked Integration and differentiation of an approximation to a function - order of approximation
May
8
accepted Scaling a function with two 'asymptotes' of which one is non-constant
Mar
13
comment Scaling a function with two 'asymptotes' of which one is non-constant
The slope would be fixed if that's what you mean. Essentially it will be the same as the graph in my question but with all curves having (all the same) slope $dy/dx\neq0$ at $x=0$ instead of the current case with $dy/dx=0$ at $x=0$
Mar
13
comment Scaling a function with two 'asymptotes' of which one is non-constant
Just a quick follow-up, if the lefthand asymptote is also a linear function instead of a constant, could I still apply a similar transformation?!
Mar
13
revised Scaling a function with two 'asymptotes' of which one is non-constant
changed small error in calculation of t
Mar
13
suggested suggested edit on Scaling a function with two 'asymptotes' of which one is non-constant
Mar
12
comment Scaling a function with two 'asymptotes' of which one is non-constant
I was indeed looking for a linear transformation. Sorry, forgot to mention that. Thanks for the answer! - Just for future reference: the choice of $t$ to map everything on the red curve in my case would be $t=(1-y_{as})/(y_0-y_{as})$ where $y_{as}$ is the value of the horizontal asymptote of the given function
Mar
12
asked Scaling a function with two 'asymptotes' of which one is non-constant