Michiel
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 Aug 6 comment What is this semicircle-like shape called? @Semiclassical cutting the major axis of the stadium would result in what is often called an extended or elongated semicircle, so perhaps semi-stadium is not that bad?! Aug 6 asked What is this semicircle-like shape called? Aug 2 accepted Area of the polygon formed by cutting a cube with a plane Aug 2 comment Area of the polygon formed by cutting a cube with a plane Great, thank you! Aug 2 comment Area of the polygon formed by cutting a cube with a plane Terrific explanation! Quick question: is there an easy way to deal with the case for which $m_i=0$ occurs? Or should I just compute the limit using l'hopital's rule? Aug 2 comment Area of the polygon formed by cutting a cube with a plane @CalvinLin I will certainly try that, thanks! I do wonder whether that easily generalizes to polygons with a different number of vertices (due to a different cut of the box) Aug 2 comment Area of the polygon formed by cutting a cube with a plane @StephenNand-Lal Good point, completely forgot the word for it. Yes I do, edited it. Aug 2 asked Area of the polygon formed by cutting a cube with a plane Jul 26 awarded Altruist Jul 20 awarded Investor Jul 2 awarded Curious May 9 accepted Integration and differentiation of an approximation to a function - order of approximation May 8 comment Integration and differentiation of an approximation to a function - order of approximation So indeed the order of the approximation changes with integration/differentation?! Interesting, I wasn't expecting that! May 8 asked Integration and differentiation of an approximation to a function - order of approximation May 8 accepted Scaling a function with two 'asymptotes' of which one is non-constant Mar 13 comment Scaling a function with two 'asymptotes' of which one is non-constant The slope would be fixed if that's what you mean. Essentially it will be the same as the graph in my question but with all curves having (all the same) slope $dy/dx\neq0$ at $x=0$ instead of the current case with $dy/dx=0$ at $x=0$ Mar 13 comment Scaling a function with two 'asymptotes' of which one is non-constant Just a quick follow-up, if the lefthand asymptote is also a linear function instead of a constant, could I still apply a similar transformation?! Mar 13 revised Scaling a function with two 'asymptotes' of which one is non-constant changed small error in calculation of t Mar 13 suggested approved edit on Scaling a function with two 'asymptotes' of which one is non-constant Mar 12 comment Scaling a function with two 'asymptotes' of which one is non-constant I was indeed looking for a linear transformation. Sorry, forgot to mention that. Thanks for the answer! - Just for future reference: the choice of $t$ to map everything on the red curve in my case would be $t=(1-y_{as})/(y_0-y_{as})$ where $y_{as}$ is the value of the horizontal asymptote of the given function