415 reputation
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age 24
visits member for 1 year, 7 months
seen Apr 6 at 22:20

Grad student in Applied Math/Computational Biology by mornings, trying to build community with other queer people of color by afternoons, beer and bourbon enthusiast by nights. Interested in progressive politics, fitness, and of course ice cream.


Dec
20
awarded  Yearling
Sep
24
comment Show the mapping is $C^1$
Oh ok, I see that now. But then why is the sup-norm important? Is it simply because it makes C([0, 1]) a Banach space?
Sep
23
asked Show the mapping is $C^1$
May
10
answered equivalency of weak and strong convergence
May
10
comment How to prove a limit with a recurrence?
you might look here: math.stackexchange.com/questions/234814/…
May
9
comment How I can find the expected value of $G$?
have you read the wiki page on the negative binomial? It explains there what you would plug in and tells you the pmf, from which you can calculate expectation.
May
8
answered Find the volume of a regular Region in $\mathbb {R^{3}}$
May
8
answered Ratios/Proportions of numbers: problem solving
Apr
8
answered Differentiation confusion
Apr
8
comment Proof for two sequences producing the maximum value when sorted
I assume you actually mean $x_1 y_1 + x_2 y_2 + \ldots + x_n y_n$? And your contradictory assumption needs modification. 1) Just because you assume $S$ is not a maximum does not mean that $S$ is now a minimum. 2) You don't want to change the given, which is that $x_1, x_2, \ldots, x_n$ and $y_1, y_2, \ldots y_n$ are sorted in non decreasing order.
Feb
23
awarded  Commentator
Feb
23
accepted The Legendre Transform of Bernoulli r.v.s
Feb
23
comment The Legendre Transform of Bernoulli r.v.s
Ah, that makes sense. One more question: so I got $\alpha_\beta = \log(\frac{\beta(1 - p)}{p(1 - \beta)})$. How do I calculate $H(\alpha_\beta) = -\log E(\frac{\beta (1 - p)}{p (1 - \beta)})^X = \log E(\frac{p (1 - \beta)}{\beta (1 - p)})^X$? Based on the statement that should give $\log(\frac{1 - \beta}{1 - p})$ for $\beta \in [0, 1]$, but I don't know how to calculate that.
Feb
23
comment Legendre transform of log moment function
$e^{\lambda \text{ esssup } X} \geq Ee^{\lambda X}$, so take the logarithms of both sides, then divide by $\lambda$, and take the limit as $\lambda \rightarrow +\infty$. Since $\frac{\Lambda(\lambda)}{\lambda} = \Lambda'(\lambda)$ you're done.
Feb
22
asked The Legendre Transform of Bernoulli r.v.s
Feb
22
answered Legendre transform of log moment function
Feb
6
comment Maclaurin expansion of $\sqrt{\cos 2x}$ and $\tan^2 x$ up to degree 4
Not really, if you only need up to degree 4 then squaring will give you the 4 terms with relative ease.
Feb
5
comment Maclaurin expansion of $\sqrt{\cos 2x}$ and $\tan^2 x$ up to degree 4
Are you sure they want you to find the Maclaurin expansion of $\sqrt{\cos(2x)}$? It really is just horrible differentiation with no visible pattern, but it doesn't seem like a very useful exercise if that is the case. The one for $\tan^2(x)$ can be found more easily by simply squaring the Maclaurin expansion for $\tan(x)$.
Feb
5
answered Expression for $E[|X - E[X]|^3]$
Feb
5
awarded  Scholar