meta user
network profile
| bio | website | toolserver.org/~geohack/… |
|---|---|---|
| location | Stockholm, Sweden | |
| age | ||
| visits | member for | 5 months |
| seen | 1 hour ago | |
| stats | profile views | 126 |
|
May 16 |
awarded | Enthusiast |
|
May 11 |
comment |
Solving $(2x-1)\ln5=\ln2 + x\ln3$ for $x$ This is a linear equation in $x$. Can you solve it for $x$ if you treat the logarithms as constants? If yes, then look up the logarithm laws to simplify the expression for $x$. |
|
May 11 |
awarded | Citizen Patrol |
|
May 11 |
awarded | Student |
|
May 11 |
asked | Natural extension of the divisor function $\sigma$ to the complex integers $\mathbb{Z}[i]$ |
|
May 10 |
comment |
Last 2 numbers of the product of divisors @IvanLoh I have replaced the calculations with your observations, thank you! |
|
May 10 |
revised |
Last 2 numbers of the product of divisors added Ivan Loh's improvement |
|
May 9 |
comment |
Last 2 numbers of the product of divisors In the comment above, I used Euler's theorem and the binomial theorem. |
|
May 9 |
reviewed | No Action Needed Automata: 1=2, 2= 26, 3=1054, 4=5768, 5 =139314069504, 6 = ??? |
|
May 9 |
reviewed | No Action Needed Local Maxima in this function |
|
May 9 |
revised |
How to derive $\cos\frac{n\pi}{3}=\frac{1+3(-1)^{[\frac{n+1}{3}]}}{4}$ went further |
|
May 9 |
comment |
Last 2 numbers of the product of divisors @darenn I used that $$21^{(53^3)}=21^{\displaystyle{\sum_{k=0}^3\binom{3}{k}40^k13^{3-k}}}\equiv_{100}21^{(13^3)}$$ and $$41^{61}=41^{\phi(100)+21}\equiv_{100}41^{21}.$$ |
|
May 9 |
revised |
$X∈M_{m×1}(F)$ and $Y∈M_{1×n}(F)$: A Range Dimension Implication improved formatting and tags |
|
May 9 |
suggested | suggested edit on $X∈M_{m×1}(F)$ and $Y∈M_{1×n}(F)$: A Range Dimension Implication |
|
May 9 |
revised |
What is $57^{46}$ divided by 17? improved formatting |
|
May 9 |
suggested | suggested edit on What is $57^{46}$ divided by 17? |
|
May 9 |
awarded | Custodian |
|
May 9 |
reviewed | No Action Needed What is $57^{46}$ divided by 17? |
|
May 9 |
comment |
Last 2 numbers of the product of divisors @darenn Yes, I admit I used some help with the calculations. However, if necessary, all of this could be done with pen and paper, and some time. |
|
May 9 |
comment |
Proving that every $2\times 2$ matrix $A$ with $A^2 = -I$ is similar to a given matrix @David It was an ansatz; it seemed like two degrees of freedom would suffice. Naturally, to simplify as much as possible, I first tried $$P=\pmatrix{0&A\\B&0},$$ but this implied that $A=B=0$. Seeing where it went wrong, I chose $$P=\pmatrix{1&A\\B&0}$$ instead. |
