5,616 reputation
1736
bio website math.boisestate.edu
location Boise, ID
age 24
visits member for 1 year, 11 months
seen 1 hour ago

I am a student in Mathematics at Boise State University.
My main interests lie in the realms of set theory and topology, but I have a deep appreciation for most fields of mathematics.

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13h
comment let $(a_n)$ be a sequence of real numbers such that $|a_{n+1}-a_n|\leq \frac {n^2}{2^n}$ for all $n\in \mathbb N$. Then
@copper.hat Maybe you can explain how gloom's solution is lacking, he applied some infinite triangle inequality thing that isn't really a triangle inequality thing--his indices are going upwards not downwards as in your hint. It seems that his solution is being upvoted which has correlation with correct-ness but in my opinion his solution is lacking...
13h
comment let $(a_n)$ be a sequence of real numbers such that $|a_{n+1}-a_n|\leq \frac {n^2}{2^n}$ for all $n\in \mathbb N$. Then
I have written a solution, hopefully it makes sense to the community.
13h
revised let $(a_n)$ be a sequence of real numbers such that $|a_{n+1}-a_n|\leq \frac {n^2}{2^n}$ for all $n\in \mathbb N$. Then
I messed up
14h
revised let $(a_n)$ be a sequence of real numbers such that $|a_{n+1}-a_n|\leq \frac {n^2}{2^n}$ for all $n\in \mathbb N$. Then
added 77 characters in body
14h
answered let $(a_n)$ be a sequence of real numbers such that $|a_{n+1}-a_n|\leq \frac {n^2}{2^n}$ for all $n\in \mathbb N$. Then
14h
comment let $(a_n)$ be a sequence of real numbers such that $|a_{n+1}-a_n|\leq \frac {n^2}{2^n}$ for all $n\in \mathbb N$. Then
You're not quite applying the hint from copper.hat. He is applying the triangle inequality multiple times downwards, I'm not sure what's happening with your explanation.
14h
comment let $(a_n)$ be a sequence of real numbers such that $|a_{n+1}-a_n|\leq \frac {n^2}{2^n}$ for all $n\in \mathbb N$. Then
My cat's name is Cauchy
1d
comment Number of functions from domain to codomain
@Mark sure no problem.
1d
comment Number of functions from domain to codomain
@Mark There are $b^a$ number of functions.
2d
awarded  Nice Answer
Dec
11
answered How is the area of this triangle calculated
Dec
11
comment What does non-zero integer mean?
do you know what zero is? do you know what non is?
Dec
11
comment What is a counting number?
hahhahhahhahaha
Dec
9
awarded  Caucus
Dec
4
reviewed Approve A difficult trigonometry problem
Dec
4
accepted No-where dense sets in the reals
Dec
4
comment No-where dense sets in the reals
@bof That makes sense. Yeah, I didn't think very deeply about the question...
Dec
4
comment No-where dense sets in the reals
@AsafKaragila Yes!!! those are the things that I mean by that. I guess weird to me is just simply things I have less familiarity with. I've played with vitali sets, and cantor space a lot-- fat cantor sets yeah, those are nice. But bernstein sets! I need to play with those some more... I'm a newcomer to desc. set theory so weird means unfamiliar :)
Dec
4
comment No-where dense sets in the reals
However!!!!! Great answer.
Dec
4
comment No-where dense sets in the reals
Guess what I'm looking for isn't there... I'm trying to think of some way something weird could happen--but alas too much is known about $\mathbb{R}$ at this point....