136 reputation
7
bio website
location
age
visits member for 1 year, 8 months
seen Jun 17 at 13:31

Jul
2
awarded  Curious
Apr
9
comment Sum of closed and compact set in a TVS
Would you please explain how you conclude, in the end, that $y=a+b$ should be in $V_{a_i}$ for some $i$ ? I agree that $a \in (V_{a_i} - B)$ for some $i$, but this does not (directly) imply that $a+b \in V_{a_i}$ for some $i$.
Feb
10
accepted If $X$ is a compact metric space, $Homeo(X)$ is second countable
Feb
9
asked If $X$ is a compact metric space, $Homeo(X)$ is second countable
Jan
28
comment Conditional expectation of random walking
I don't see what could be wrong... This problem seems really simple. If you know $S_n$, the expected value for $S_{n+1}$ is trivially $S_n$ plus the expected value of $Y_{n+1}$ since the $Y_i$ are independent variables. I don't think there is a trap...
Jan
28
accepted Pointwise convergence to a constant function on a compact space
Jan
28
comment Pointwise convergence to a constant function on a compact space
Thanks a lot for your answer! Your counterexample is indeed simple, but not totally easy to find. I would have prefered an affirmative answer, but that's not your fault :-)
Jan
26
asked Pointwise convergence to a constant function on a compact space
Jun
5
accepted Space $H^1([0, T], H^{-1}(U))$
Jun
5
comment Space $H^1([0, T], H^{-1}(U))$
Oh yes, I found your definition in Evan's! Thank you :)
Jun
5
comment Space $H^1([0, T], H^{-1}(U))$
But what would this product between $\varphi'$ and $u$ mean in this context where $X = H^{-1}(U)$?
Jun
5
revised Space $H^1([0, T], H^{-1}(U))$
edited body
Jun
5
comment Space $H^1([0, T], H^{-1}(U))$
Oh yeah sorry, I correct it.
Jun
5
comment Prove/disprove: There isn't any graph with an even number of vertices and an odd number of edges that contains Euler's circuit.
Yes, if the graph is connected, you can easily prove the proposition, but if it isn't, your example is correct. Now you have to see if the man who wrote the proposition just forgot the word "connected" or if he is expecting a disconnected example as yours...
Jun
5
asked Space $H^1([0, T], H^{-1}(U))$
May
22
revised Uniform convergence and uniform boundedness
added 2 characters in body
May
22
comment Uniform convergence and uniform boundedness
Actually, they say "... is majorised (see p.67) ...", and the definition of majorised is precisely, page 67 : "Let $f$, $F$ be functions with domain in $\mathbb{R}^n$ and range in $\mathbb{R}^m$, of class $C^\infty$ in a neighborhood of the origin. We say $f$ is majorised by $F$, if $|D^\alpha f_k(0)| \leq D^\alpha F_k(0)$ for all $\alpha \in \mathbb{Z}^n$ and all $k$." I suppose that what they mean here is that each term of the series $(*)$ is less than the corresponding term of the series of $U$. We have proved it, as I've just added in my first post.
May
22
revised Uniform convergence and uniform boundedness
added 139 characters in body
May
21
awarded  Commentator
May
21
comment Uniform convergence and uniform boundedness
Sorry but you don't really help me... I've already searched for hours and your hints which are just reformulation of the definition of uniform convergence don't help me a lot. I've succeeded to prove the uniform convergence on every compact, using the boundedness of $U$, I'll do with that. Thank you for your time ;)