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Jul
18
awarded  Popular Question
Jul
17
awarded  Popular Question
Jul
4
awarded  Popular Question
Jun
18
revised How to generate feasible $H$-conjugate descent search directions in convex subset
deleted 5 characters in body; edited title
Jun
18
comment How to generate feasible $H$-conjugate descent search directions in convex subset
Yes, you're correct :) corrected the post
Jun
18
revised How to generate feasible $H$-conjugate descent search directions in convex subset
deleted 5 characters in body; edited title
Jun
18
asked How to generate feasible $H$-conjugate descent search directions in convex subset
Jun
11
asked Making projected search directions conjugate
May
15
comment Why does $\frac{\textbf{g}^T\textbf{d}}{\textbf{d}^T\textbf{H}\textbf{d}}$ give the maximum of function $\mathcal{D}(\textbf{x}+\lambda\textbf{d})$
Thank you :) Appreciate it
May
15
comment Why does $\frac{\textbf{g}^T\textbf{d}}{\textbf{d}^T\textbf{H}\textbf{d}}$ give the maximum of function $\mathcal{D}(\textbf{x}+\lambda\textbf{d})$
Thank you, the reference material is in my post if you want to see it :)
May
15
comment Why does $\frac{\textbf{g}^T\textbf{d}}{\textbf{d}^T\textbf{H}\textbf{d}}$ give the maximum of function $\mathcal{D}(\textbf{x}+\lambda\textbf{d})$
Thank you very much =)
May
15
accepted Why does $\frac{\textbf{g}^T\textbf{d}}{\textbf{d}^T\textbf{H}\textbf{d}}$ give the maximum of function $\mathcal{D}(\textbf{x}+\lambda\textbf{d})$
May
14
revised Why does $\frac{\textbf{g}^T\textbf{d}}{\textbf{d}^T\textbf{H}\textbf{d}}$ give the maximum of function $\mathcal{D}(\textbf{x}+\lambda\textbf{d})$
edited body
May
14
comment Why does $\frac{\textbf{g}^T\textbf{d}}{\textbf{d}^T\textbf{H}\textbf{d}}$ give the maximum of function $\mathcal{D}(\textbf{x}+\lambda\textbf{d})$
Okay, sorry about that. What do you want me to do? I'm not sure what you meant exactly :) P.S. I changed the question back to the way it was before you commented :) Thank you
May
14
comment Why does $\frac{\textbf{g}^T\textbf{d}}{\textbf{d}^T\textbf{H}\textbf{d}}$ give the maximum of function $\mathcal{D}(\textbf{x}+\lambda\textbf{d})$
Roger that @S.B. :) It wasn't so hard after all x) Thank you, P.S. if you want to post your comment as answer I can accept it.
May
14
revised Why does $\frac{\textbf{g}^T\textbf{d}}{\textbf{d}^T\textbf{H}\textbf{d}}$ give the maximum of function $\mathcal{D}(\textbf{x}+\lambda\textbf{d})$
edited body
May
14
comment Why does $\frac{\textbf{g}^T\textbf{d}}{\textbf{d}^T\textbf{H}\textbf{d}}$ give the maximum of function $\mathcal{D}(\textbf{x}+\lambda\textbf{d})$
Aah okay, so the equation follows simply by taking the derivative of $\mathcal{D}$ w.r.t $\lambda$ and equating to zero? In the unconstrained case I mean :)
May
14
revised Why does $\frac{\textbf{g}^T\textbf{d}}{\textbf{d}^T\textbf{H}\textbf{d}}$ give the maximum of function $\mathcal{D}(\textbf{x}+\lambda\textbf{d})$
added 80 characters in body
May
14
asked Why does $\frac{\textbf{g}^T\textbf{d}}{\textbf{d}^T\textbf{H}\textbf{d}}$ give the maximum of function $\mathcal{D}(\textbf{x}+\lambda\textbf{d})$
May
14
awarded  Popular Question