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1d
revised Integral: $\int_{-\infty}^{\infty} \frac{dx}{(e^x+x+1)^2+\pi^2}$
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1d
revised Integral: $\int_{-\infty}^{\infty} \frac{dx}{(e^x+x+1)^2+\pi^2}$
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1d
revised Calculate $\int_0^1 \ \int_0^1 \ x \sin \lvert x^2-y^2 \lvert \; dx \; dy$
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1d
answered Calculate $\int_0^1 \ \int_0^1 \ x \sin \lvert x^2-y^2 \lvert \; dx \; dy$
1d
awarded  Revival
1d
comment Evaluate $\int_{-\infty}^{\infty}x^2 e^{-\alpha x^2+\beta x}dx$
See @Did's comments re switching the order of integration and differentiation over a noncompact interval.
1d
comment Evaluate $\int_{-\infty}^{\infty}x^2 e^{-\alpha x^2+\beta x}dx$
Funny how this solution is getting picked apart and downvoted because it is unclear how it justified swapping the differentiation and integration operations, yet the other solution, which does the same thing without even attempting to justify anything, got upvotes and no critical comments.
1d
revised contour integration of a function with two branch points .
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1d
revised contour integration of a function with two branch points .
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1d
revised contour integration of a function with two branch points .
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1d
comment How to calculate inverse laplace of $e^{a\sqrt s}$?
math.stackexchange.com/questions/347933/…
1d
answered contour integration of a function with two branch points .
Feb
10
awarded  Enlightened
Feb
10
awarded  Nice Answer
Feb
9
revised Solving Laguerre coefficients with Integral?
added 108 characters in body
Feb
9
answered Solving Laguerre coefficients with Integral?
Feb
9
comment To test convergence of improper integral $ \int_{0}^{\infty} \frac{x\log(x)}{(1+x^2)^2}\, \mathrm dx$
@TaylorTed: you don't need to do that just to prove convergence. That may be a useful technique to evaluate the integral though. I personally prefer using the residue theorem.
Feb
9
comment To test convergence of improper integral $ \int_{0}^{\infty} \frac{x\log(x)}{(1+x^2)^2}\, \mathrm dx$
That works at infinity. Also note that $\lim_{x \to 0} x \log{x} = 0$ and you are done because there are no poles on the $x$-axis. BTW the integral may be evaluated using any number of techniques.
Feb
8
revised Definite integral of a continued fraction function
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Feb
8
comment Definite integral of a continued fraction function
@user170231: yes, you're right. Thanks for the catch.