1,692 reputation
926
bio website fuz.su/~fuz
location Berlin, Germany
age 20
visits member for 3 years, 11 months
seen yesterday

I am a student of computer science and mathematics at the Humboldt University of Berlin.


Mar
29
comment Find a closed form for this sequence: $a_{n+1} = a_n + a_n^{-1}$
That's still only an asymptotic.
Mar
29
asked Find a closed form for this sequence: $a_{n+1} = a_n + a_n^{-1}$
Mar
23
revised factorization of a^n+1?
Encapsulate $\LaTeX$ into dollars.
Mar
23
suggested approved edit on factorization of a^n+1?
Mar
20
revised Salt concentration as a function of time
Use LaTeX formatting.
Mar
20
revised Prove inequality: When $n > 2$, $n! < {\left(\frac{n+2}{\sqrt{6}}\right)}^n$
beautify formatting
Mar
20
suggested approved edit on Prove inequality: When $n > 2$, $n! < {\left(\frac{n+2}{\sqrt{6}}\right)}^n$
Mar
20
suggested approved edit on Salt concentration as a function of time
Mar
19
revised Create Fisheye from image
Changed formating
Mar
19
suggested approved edit on Create Fisheye from image
Mar
8
accepted How to prove that a polynomial of degree $n$ has at most $n$ roots?
Mar
8
comment How to prove that a polynomial of degree $n$ has at most $n$ roots?
@Moron: Okay. Thank you for this.
Mar
8
comment How to prove that a polynomial of degree $n$ has at most $n$ roots?
@Moron: It's a part of the fundamental theorem. Consider this question as answered.
Mar
8
comment How to prove that a polynomial of degree $n$ has at most $n$ roots?
@Moron: I'm not (yet) in university. This isn't homework. Just asking this as a part to proof my last question. I'm asking this because I didn't knew, that this is a fundamental theorem of algebra.
Mar
8
asked How to prove that a polynomial of degree $n$ has at most $n$ roots?
Mar
6
revised Why does 0! = 1?
added 122 characters in body
Mar
6
answered Why does 0! = 1?
Mar
5
revised Equality of polynomials: formal vs. functional
added 47 characters in body
Mar
5
accepted Equality of polynomials: formal vs. functional
Mar
5
comment How to prove the equality $\sum_{j=0}^n (x)^j (-1)^{n-j} \left\{{n \atop j}\right\} = x^n$?
Is your $(x)^j$ the same as $x^\overline{j}?$