| bio | website | about:blank |
|---|---|---|
| location | Berlin, Germany | |
| age | 18 | |
| visits | member for | 2 years, 5 months |
| seen | Jun 13 at 1:59 | |
| stats | profile views | 232 |
I'm a highschool student from Germany interested in functional programming, especially Haskell.
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May 9 |
comment |
How to prove that $\lim\limits_{x\to0}\frac{\sin x}x=1$? @CutieKrait We defined $\sin$ by geometrical means. |
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Apr 2 |
accepted | Why is it impossible to define multiplication in Presburger arithmetic? |
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Apr 2 |
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Why is it impossible to define multiplication in Presburger arithmetic? Ah, I see. Thank you for this answer. |
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Mar 31 |
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Why is it impossible to define multiplication in Presburger arithmetic? @MJD How are these axioms? |
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Mar 31 |
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Why is it impossible to define multiplication in Presburger arithmetic? @MJD Presburger arithmetic is an axiomatic system. People claim that it is impossible to define multiplication within this system. Why? |
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Mar 30 |
asked | Why is it impossible to define multiplication in Presburger arithmetic? |
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Mar 4 |
awarded | Good Question |
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Feb 23 |
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How to prove that $\lim\limits_{x\to0}\frac{\sin x}x=1$? How do we know that sin x is equal to x for small values? |
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Jan 1 |
awarded | Yearling |
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Dec 12 |
awarded | Nice Question |
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Dec 5 |
awarded | Nice Answer |
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Oct 31 |
awarded | Taxonomist |
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Oct 23 |
awarded | Popular Question |
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Oct 18 |
asked | Squaring modulo n — is there a systematic way to generate the fixpoints? |
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Sep 30 |
awarded | Popular Question |
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Sep 8 |
revised |
The inverse of the inscribed angle theorem added 44 characters in body |
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Sep 8 |
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The inverse of the inscribed angle theorem I am sorry. I usually don't ignore the orientation of angles. I should've made that clear beforehand. |
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Sep 8 |
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The inverse of the inscribed angle theorem Nice and easy. Thank you! |
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Sep 8 |
accepted | The inverse of the inscribed angle theorem |
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Sep 8 |
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The inverse of the inscribed angle theorem In the second case, the sign of the angle $\angle ACB$ is negative. The equation $2\angle ACB=\angle AMB$ does not holds if the signs do not match. |