1,687 reputation
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bio website fuz.su/~fuz
location Berlin, Germany
age 20
visits member for 3 years, 11 months
seen yesterday

I am a student of computer science and mathematics at the Humboldt University of Berlin.


2d
revised How to prove that $\lim\limits_{x\to0}\frac{\sin x}x=1$?
formatting, spelling
2d
suggested approved edit on How to prove that $\lim\limits_{x\to0}\frac{\sin x}x=1$?
Dec
8
awarded  Caucus
Dec
8
accepted How to construct a polynomial from a radix-term?
Dec
8
comment How to construct a polynomial from a radix-term?
Ah yes, that makes sense. I'm sorry for my confusion.
Dec
8
comment How to construct a polynomial from a radix-term?
That was a typo, it should have been $\alpha\in\mathbb Q\setminus\{0\}$. I'm a bit confused about how you explain the translation that makes a polynomial $p'$ with $p'(\alpha^{-1})=0$ from a polynomial $p$ with $p(\alpha)=0$. Your explanation does not really enlightens me. Maybe that's just because I am a bit hungover.
Dec
8
comment How to construct a polynomial from a radix-term?
I'm afraid I might have misunderstood something, but what guarantees that $\alpha\in\mathbb Q\{0\}$? Isn't $\alpha$ the value of an arbitrary algebraic expression with $\alpha\neq0$?
Dec
8
comment How to construct a polynomial from a radix-term?
What do you do if we take a negative power over a subterm?
Dec
8
comment How to construct a polynomial from a radix-term?
How can we prove that for every polynomial with integer coefficients $\sqrt 2$ is a root of, $-\sqrt 2$ is a root, too?
Dec
8
comment How to construct a polynomial from a radix-term?
@HenningMakholm Ah, that makes sense. Thank you for pointing out the correct term.
Dec
7
asked How to construct a polynomial from a radix-term?
Nov
27
comment Showing that $\lim_{x\to\infty}\left(\sqrt{x^2+c}-x\right)=0$
I feel dumb now.
Nov
27
accepted Showing that $\lim_{x\to\infty}\left(\sqrt{x^2+c}-x\right)=0$
Nov
27
revised Showing that $\lim_{x\to\infty}\left(\sqrt{x^2+c}-x\right)=0$
add condition on c
Nov
27
asked Showing that $\lim_{x\to\infty}\left(\sqrt{x^2+c}-x\right)=0$
Nov
11
comment How to prove that $\lim\limits_{x\to0}\frac{\sin x}x=1$?
In a triangle $ABC$ with right angle in $ACB$ we define $\sin BAC=BC/AC$. This is the “geometrical” definition for $\sin$ we used.
Nov
7
awarded  Favorite Question
Sep
24
comment Reducing the time to calculate Collatz sequences
@sp1rs No. See the answers linking here.
Jul
2
awarded  Curious
Jul
2
awarded  Popular Question