無色受想行識

less info
101 reputation
2
bio website
location
age
visits member for 1 year, 9 months
seen Mar 1 at 8:57

Mar
1
awarded  Editor
Mar
1
awarded  Citizen Patrol
Dec
11
comment Taylor expansion of $\arccos(1-x)$ around $x=0$ to two terms
When I try to take the derivative of $\frac {\arccos(1-x)}{\sqrt x}$ I get $\frac{ \frac {-\sqrt x}{\sqrt{2x-x^2}} + \frac {\arccos(1-x) }{2 \sqrt {x}^3}}{x}$ = $-\frac{1}{\sqrt{2x^2-x^3}} $ which is still bad at $x=0$. Is it just that my algebra is wrong?