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network profile
| bio | website | |
|---|---|---|
| location | ||
| age | ||
| visits | member for | 5 months |
| seen | Mar 17 at 21:53 | |
| stats | profile views | 40 |
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Mar 15 |
asked | probability generating function with die |
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Mar 11 |
comment |
Find reduction formula using integration by parts I don't understand how you've got from the second line to the third line which begins to look like the result needed. |
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Mar 11 |
comment |
Reduction formula Integrating by parts twice for the second part seems difficult. |
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Mar 10 |
comment |
Find reduction formula using integration by parts @anorton I haven't done anything really. |
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Mar 10 |
asked | Find reduction formula using integration by parts |
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Mar 10 |
asked | Reduction formula |
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Mar 10 |
asked | Isomorphism with abelian groups |
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Feb 10 |
comment |
CDF and conditional probability I seem to get $$ \int_0^{\infty} \lambda e^{tx-t\lambda} dx = [\frac{\lambda e^{tx-t\lambda}}{t}]_0^{\infty} $$ if $t$ is treated as a constant. |
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Feb 10 |
comment |
CDF and conditional probability I seem to be dealing with a partial integral here. I am sure I am doing something wrong. Please take a look at this: $\int_0^{\inf} \lambda e^{-\lambda t} e^{Tx} dx$ |
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Feb 10 |
accepted | CDF and conditional probability |
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Feb 8 |
comment |
CDF and conditional probability Please see my edit about the MGF. |
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Feb 8 |
comment |
CDF and conditional probability $P(T>t)=1-(1-e^{-\lambda t})=e^{-\lambda t}$. If that is right, the rest of the proof is easy. Also please see my edit about the MGF. |
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Feb 8 |
awarded | Supporter |
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Feb 8 |
revised |
CDF and conditional probability added 10 characters in body |
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Feb 8 |
revised |
CDF and conditional probability added 10 characters in body |
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Feb 8 |
asked | CDF and conditional probability |
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Feb 8 |
comment |
Gambler tosses coin PGF I know the definition but I don't know how to calculate it. I suggested the third central moment because that is one of the ways that you can do it, but I don't think that is the best way. |
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Feb 7 |
accepted | Polar coordinates parameters |
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Feb 6 |
asked | Polar coordinates parameters |
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Feb 5 |
comment |
Maclaurin expansion of two functions @Alex working is needed |
