Jack Forest
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 Dec 5 comment Another Ordered Quadruples Question Also for the part where you get $2^4*C(49,3)=294784$ , when I calculate $C(49,3)$ I do get 18424 but when I do $2^4*C(49,3)$ I get 147392 am I making a mistake? Dec 5 comment Another Ordered Quadruples Question Do you say positive integers and not just integers because the value of the x's will definitely be positive since we are looking for the absolute value? More to the point do we not have to count the possibilities for if the value of x is negative? Dec 5 asked Another Ordered Quadruples Question Dec 5 comment Ordered Quadruples Question I reread all of this when I woke up this morning and now I believe that I do understand the question and the answer, does the fact that it is asking about the set of natural numbers raised to the fourth not matter? Dec 5 awarded Commentator Dec 5 comment Ordered Quadruples Question Ok I think I understand thank you very much, just to be clear x1+x2+x3+x4<=50 is the same as x1+x2+x3+x4+x5=50? Dec 5 comment Ordered Quadruples Question Thank you that was very helpful. How does the answer change when you consider <= 50 instead of = 50 and is the answer the same whether you have 4 or 5 x's? Dec 5 comment Ordered Quadruples Question I'm sorry I just realized I made a mistake in the problem I didn't mean quadrupled I meant raised to the 4th power. Dec 5 comment Ordered Quadruples Question The number of solutions. Dec 5 comment Ordered Quadruples Question Yes, please more help I am still baffled. Dec 5 comment If $p$ is a prime number greater than $2$ and $k$ is a natural number so that \$k