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 Feb27 asked What's a singular differential equation? Feb27 comment Variable change in this partial differential equation @Kaster Ok thanks. Feb27 asked Variable change in this partial differential equation Feb26 comment Dimension of a space @julien ok..... Feb26 comment Dimension of a space @julien That's the teqhnical name. In $\mathbb{R}^3$, the vectors $(1,0,0),(0,1,0),(0,0,1),(1,1,0)$ generate the space, but they're not "our" minimal basis because you can remove one of the vector and still have a basis. Feb26 comment Dimension of a space Where can I see a proof of $c^{\aleph_0}=c$? Feb26 comment Dimension of a space @julien It maybe a mistraslation from spanish, I translated it literally and probably the english word is different: it's a base that generates the full space, but whose members are linearly independent. Feb26 revised Dimension of a space deleted 9 characters in body Feb26 comment Dimension of a space @TobiasKildetoft That was actually added by me under complete ignorance. I deleted it. Feb26 comment Dimension of a space @TobiasKildetoft Could you please develop that answer. I'm very interested in it. I just don't get that equality. Feb26 asked Dimension of a space Feb26 comment Linear Algebra Linear Independence @JacobBlack So what's your point? Feb25 comment Differential Equation Setup for an RLC Circuit If you're doubt is about the physical analysis to get to the right equation, you may get better help in physics.SE than here. If you're question is about solving that equation, the this is the place, but it looks like the first one. Feb25 answered Linear Algebra Linear Independence Feb25 comment Scalar triple product - why equivalent to determinant? @JohnSmith Glad I helped! Feb25 answered Scalar triple product - why equivalent to determinant? Feb24 comment Why is the area under a curve the integral? That was awesome! Feb24 answered Making up for wasted high school years - where should I begin? Feb23 comment Show that this entire function is polynomial. @GitGud Yes thanks. Feb23 comment Show that this entire function is polynomial. If a set of points is bounded and discrete, can you then conclude is finite? Any sequence that converges is bounded and discrete, and infinite, like $\sum_0^\infty \frac{1}{2^k}$