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NTS


6h
awarded  Caucus
Dec
1
awarded  Yearling
Nov
12
reviewed Approve $e^{1/z}$ and Laurent expansion
Sep
30
awarded  Explainer
Jul
2
awarded  Curious
Jun
27
comment Topologies on n-manifolds
Well... by definition of a manifold, any topology of a manifold must the same topology (o equivalent) to the usual topology, as it must be locally homeomorphic to $\mathbb R^n$ with the usual topology.
Jun
25
comment Geodesics of this metric
Ok, I see it. Thank you very much
Jun
25
accepted Geodesics of this metric
Jun
25
comment Geodesics of this metric
Thank you. How do you get from $\ddot x-C^2 /x^3=0$ to the solution $x(t)$?
Jun
25
revised Geodesics of this metric
added 164 characters in body
Jun
25
asked Geodesics of this metric
Jun
24
comment Let $G=\mathbb Z_4 \times \mathbb Z_2$. Find all $H$ subgroups of $G$ of order 2, so that $G / H$ is cyclic.
Oh that was your question... I'm sorry, well We already found all the subgroups of order $2$, now do you hav any problem in computing the quotient groups $G/H$ Checking if it' cyclic is checking if the identity $H$ generates the whole group $G/H$.
Jun
24
answered Let $G=\mathbb Z_4 \times \mathbb Z_2$. Find all $H$ subgroups of $G$ of order 2, so that $G / H$ is cyclic.
Jun
24
comment Help understanding a proof in differential geometry
I see your "firstly", I just don't see why it's neccesary in the argument. The fact that there are a finite number of points in which $df$ is singular comes from the expression of $P'$, right?
Jun
24
comment Help understanding a proof in differential geometry
Thank you both, it was a lot simpler than I thought.
Jun
24
asked Help understanding a proof in differential geometry
Jun
19
accepted How to prove a $k$-$1$ differential form is simple
Jun
19
comment How to prove a $k$-$1$ differential form is simple
Ok, I think I got it. Thank you.
Jun
19
comment How to prove a $k$-$1$ differential form is simple
I see that particular case, thank you. I was trying to relate the fact that 1 forms are obviously simple and that the space they span has the same dimension as the space of k-1 forms.
Jun
19
comment How to prove a $k$-$1$ differential form is simple
@ReneSchipperus I'm sorry, in your first comment, with both you were talking about the space of $k$-$1$ forms and what else?