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 1d reviewed Approve Show that a polar equation describes a circle Jul 31 revised How following matrices equation is solved? math type Jul 31 comment How following matrices equation is solved? What do the $[]$ mean? Jul 2 comment Show that $A^k$ has eigenvalues $\lambda^k$ and eigenvectors $v$. I find your proof more simple, more direct, more general and more obvious, thus much better. Jun 24 awarded Popular Question Jun 21 awarded Tenacious Jun 19 revised Why are these curves' points called rational? added 2 characters in body Jun 19 comment Why are these curves' points called rational? Thanks for the answer and explanation Jun 19 accepted Why are these curves' points called rational? Jun 19 comment Why are these curves' points called rational? Ok, thank you very much for the answer and the example. Which by the way... is it right? $i^4+i^4=2=\sqrt 2^4=4$? Should the curve have a $2$ coefficient multiplying the $x$ and $y$ terms? Jun 19 asked Why are these curves' points called rational? Jun 17 comment Proposed proof of topological result Other than that, I find it perfect. Try to separate paragraphs though, it's a bit hard to read. Jun 17 comment Proposed proof of topological result What's $(B,d)$ and $(A,d)$? Jun 17 reviewed Approve Proposed proof of topological result Jun 17 answered How to factor $ax^{2}+bxy+cy^{2},\,a\neq 0$? Jun 17 revised $(x x^T)^{-1}$, efficient matrix inversion for matrix composed as product of a vector with itself? edited a wrong order of factor in the first denominator of the second formula Jun 12 answered what will be the parameterization of cone Jun 12 comment Solutions for $|x^2-5x+2|=4$ @BetterWorld That means they should also come as a solution when you consider the negative sign of the modulus, try it. You should discard those solutions when you get the from the positive values, and when consider the negative, $x=1$ should come out again. Jun 12 comment Solutions for $|x^2-5x+2|=4$ @BetterWorld That just means they're not solutions, because they fail to satisfy the hypothesis that $x^2-x-1$ is positive, on which the solution depends. Jun 12 reviewed Approve Limit of $\large{\frac{1}{2^x}}$ as $x \to \infty$