network profile
| bio | website | |
|---|---|---|
| location | ||
| age | ||
| visits | member for | 5 months |
| seen | Nov 30 '12 at 10:19 | |
| stats | profile views | 5 |
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Nov 30 |
awarded | Scholar |
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Nov 30 |
accepted | When does $V = \ker(f) \oplus \operatorname{im}(f)$? |
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Nov 30 |
awarded | Editor |
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Nov 30 |
comment |
When does $V = \ker(f) \oplus \operatorname{im}(f)$? Thanks! I was only concerned about the finite dimensional case anyway, I just forgot to mention it. |
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Nov 30 |
revised |
When does $V = \ker(f) \oplus \operatorname{im}(f)$? added 40 characters in body |
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Nov 30 |
comment |
When does $V = \ker(f) \oplus \operatorname{im}(f)$? @joriki: Equality. I haven't heard the term internal direct sum before, but based on the definition on Wikipedia, I think that's what I'm referring to, since $\ker(f)$ and $\operatorname{im}(f)$ are subspaces of $V$. |
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Nov 30 |
awarded | Student |
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Nov 30 |
asked | When does $V = \ker(f) \oplus \operatorname{im}(f)$? |
