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| visits | member for | 5 months |
| seen | Jan 15 at 20:15 | |
| stats | profile views | 4 |
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Dec 12 |
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About covering maps and sections! @Jason deVito I think there might be a typo in your solution |
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Dec 12 |
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Infinitely sheeted covering spaces! @JasonDeVito But since any covering space of a manifold has to be a manifold, wouldn't all the covering spaces of a connected sum of tori be homeomorphic to a connected sum of tori? |
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Dec 12 |
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About covering maps and sections! Ok. Maybe someone else could give a more thorough explanation! |
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Dec 12 |
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About covering maps and sections! @rschwieb yes,it cast doubt on my solution...I am no longer sure that what I said holds...maybe you could shed some light. |
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Dec 12 |
awarded | Commentator |
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Dec 12 |
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About covering maps and sections! @rschwieb I'm not sure i understand what you are implying? |
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Dec 12 |
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About covering maps and sections! added 66 characters in body |
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Dec 12 |
answered | About covering maps and sections! |
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Dec 12 |
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Infinitely sheeted covering spaces! Yes you are correct. My topology seems to be rusty...in this case wouldn't the proper subgroup of the fundamental group of the connected sum of tori be infinite cyclic then? Since this corresponds to some cover of the connected sum of tori then it would answer the op's question I think. |
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Dec 12 |
answered | Infinitely sheeted covering spaces! |
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Dec 7 |
awarded | Student |
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Dec 7 |
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Constructible numbers Just edited my post, right on time:) |
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Dec 7 |
awarded | Editor |
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Dec 7 |
revised |
Constructible numbers added 104 characters in body |
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Dec 7 |
asked | Constructible numbers |
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Nov 29 |
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Spectral Theorem @ Robert Israel: so is that all what the problem is asking? Namely to assert that the diagonal entries of the matrix A will be $\pm 1$ after diagonalization? It seems too simple! |
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Nov 29 |
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Spectral Theorem @ froggie: thanks! Regarding the question the only other thing I can get is that the matrix A will have real eigenvalues. |
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Nov 29 |
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Spectral Theorem Does it suffice to say something along the lines: since the matrix is symmetric and orthogonal, then the matrix A would be normal, so there is some orthogonal matrix P such that $P^tAP$ is a diagonal matrix whose entries are all 1s. Would this suffice or is it asking for more, sth else?? Thanks |
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Nov 29 |
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Spectral Theorem @gedgar: yes thats correct...however my trouble is on how to phrase my answer. |