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Dec
9
accepted Polar form of Complex numbers
Dec
6
comment Polar form of Complex numbers
How did you get $e^{i\pi100/3}$ to $e^{i\pi4/3}$
Dec
6
comment Polar form of Complex numbers
Alright, with my calculations, (not messing with ^100) I get $e^{i\pi/3}$ so I should get something like $e^{i\pi/3*100}$
Dec
6
asked Polar form of Complex numbers
Dec
4
awarded  Scholar
Dec
4
awarded  Supporter
Dec
4
accepted Complex numbers: With conjugate
Dec
4
awarded  Student
Dec
4
asked Complex numbers: With conjugate