519 reputation
212
bio website
location
age
visits member for 1 year, 7 months
seen Jul 9 at 14:54

I love math, and I love to self study math.


Jul
2
awarded  Curious
May
17
accepted Should I be worried that I am doing well in Analysis and not well in Algebra?
Dec
13
awarded  Good Question
Dec
1
accepted What are the reasons for using a semi-circle in upper half plane of $\mathbb{C}$ for contour integration?
Nov
25
asked What are the reasons for using a semi-circle in upper half plane of $\mathbb{C}$ for contour integration?
Nov
22
awarded  Yearling
Nov
7
revised Sum of absolute values and the absolute value of the sum of these values?
added 7 characters in body
Nov
7
comment Sum of absolute values and the absolute value of the sum of these values?
See my updated answer. Also as was mentioned earlier, you can try a proof by cases (see en.wikipedia.org/wiki/Proof_by_exhaustion) however that may take a bit longer.
Nov
7
revised Sum of absolute values and the absolute value of the sum of these values?
added 675 characters in body
Nov
7
comment Sum of absolute values and the absolute value of the sum of these values?
Are you familiar with the fact that, $|a| < b \Rightarrow -b < a <b$? If you are allowed to use this property you can show that $x+y > -(|x|+|y|)$; then you are done. Also as far as "applying the square" goes, we do not exactly apply it like we would in normal mathematics. We start with $|a+b|^2$ the "chain" inequalities to get what we want. I will do the first few steps in my answer.
Nov
7
revised Sum of absolute values and the absolute value of the sum of these values?
added 363 characters in body
Nov
7
answered Sum of absolute values and the absolute value of the sum of these values?
Oct
17
accepted Hints for a complex limit: Prove if $\lim_{z \to \infty} f(z)/z = 0$ then $f(z)$ is constant.
Oct
17
comment Hints for a complex limit: Prove if $\lim_{z \to \infty} f(z)/z = 0$ then $f(z)$ is constant.
ok I see thank you.
Oct
17
comment Hints for a complex limit: Prove if $\lim_{z \to \infty} f(z)/z = 0$ then $f(z)$ is constant.
then $f(z)/z$ would then tend to $a$. Which seems to be a contradiction given $\lim_{z \to \infty} f(z)/z =0$.
Oct
17
comment Hints for a complex limit: Prove if $\lim_{z \to \infty} f(z)/z = 0$ then $f(z)$ is constant.
If thats true, then how could $f$ be constant? Wouldn't $f(z) = Az + B$ for some constants A,B?
Oct
17
comment Hints for a complex limit: Prove if $\lim_{z \to \infty} f(z)/z = 0$ then $f(z)$ is constant.
If $f$ was a polynomial function then of degree $\geq 1$ then wouldn't $z$ simply divide out an one woulde be left with a limit that is constant or tending to infinity?
Oct
16
comment Hints for a complex limit: Prove if $\lim_{z \to \infty} f(z)/z = 0$ then $f(z)$ is constant.
Well we haven't covered what holomorphic is, so I don't think that I would be allowed to do that.
Oct
16
revised Hints for a complex limit: Prove if $\lim_{z \to \infty} f(z)/z = 0$ then $f(z)$ is constant.
edited body
Oct
16
comment Hints for a complex limit: Prove if $\lim_{z \to \infty} f(z)/z = 0$ then $f(z)$ is constant.
What is $K$ in that last inequality?