ashley
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 Dec 11 comment A math teacher thought of a positive integer of two digits. wore me out. i took "divisors" differently-- outside its meaning. the idea is the number of divisors should be high enough that $2$ has to be one of them for the number be ( (even) & (less than $100$) ). Dec 11 comment Strong inducti0n with 3- and 5-peso notes and can pay any number greater than 7. this is an old Q. Dec 11 comment A math teacher thought of a positive integer of two digits. Still $6$ divisors BTW, not $7$. Those multiplied giving the number itself. Fell quick for your first comment. Dec 11 comment A math teacher thought of a positive integer of two digits. $96=2^5\times3$. Hanna can't chose between $96$ and $64$ by herself. Dec 11 revised A math teacher thought of a positive integer of two digits. added 89 characters in body Dec 11 comment A math teacher thought of a positive integer of two digits. Well, work it for 7 then. this is a solution. Thanks for the warning though. Dec 11 answered A math teacher thought of a positive integer of two digits. Dec 11 comment Contrapositive of an Implication you sure about your resource ? Dec 11 revised Probability of choosing like partners added 729 characters in body Dec 11 awarded Commentator Dec 11 comment Probability of choosing like partners yup, figured trying n works. Thx again. Dec 11 awarded Custodian Dec 11 comment Probability of choosing like partners Thanks for the edit. how do you add the TeX markup in here though ? Dec 11 reviewed Approve Probability of choosing like partners Dec 11 answered Probability of choosing like partners Dec 11 revised Request theorem/Proof for $F(x)>0$ for $a0$ for \$a