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  • 0 posts edited
  • 1 helpful flag
  • 11 votes cast
Dec
11
comment A math teacher thought of a positive integer of two digits.
wore me out. i took "divisors" differently-- outside its meaning. the idea is the number of divisors should be high enough that $2$ has to be one of them for the number be ( (even) & (less than $100$) ).
Dec
11
comment Strong inducti0n with 3- and 5-peso notes and can pay any number greater than 7.
this is an old Q.
Dec
11
comment A math teacher thought of a positive integer of two digits.
Still $6$ divisors BTW, not $7$. Those multiplied giving the number itself. Fell quick for your first comment.
Dec
11
comment A math teacher thought of a positive integer of two digits.
$96=2^5\times3$. Hanna can't chose between $96$ and $64$ by herself.
Dec
11
revised A math teacher thought of a positive integer of two digits.
added 89 characters in body
Dec
11
comment A math teacher thought of a positive integer of two digits.
Well, work it for 7 then. this is a solution. Thanks for the warning though.
Dec
11
answered A math teacher thought of a positive integer of two digits.
Dec
11
comment Contrapositive of an Implication
you sure about your resource ?
Dec
11
revised Probability of choosing like partners
added 729 characters in body
Dec
11
awarded  Commentator
Dec
11
comment Probability of choosing like partners
yup, figured trying n works. Thx again.
Dec
11
awarded  Custodian
Dec
11
comment Probability of choosing like partners
Thanks for the edit. how do you add the TeX markup in here though ?
Dec
11
reviewed Approve Probability of choosing like partners
Dec
11
answered Probability of choosing like partners
Dec
11
revised Request theorem/Proof for $F(x)>0$ for $a<x<b$
added 12 characters in body
Dec
11
answered Factorizing sum of two powers.
Dec
11
answered Request theorem/Proof for $F(x)>0$ for $a<x<b$
Dec
11
comment Calculating the aspect ratio of the rotated rectangle on the image
doesn't seem possible mathematically-- not unless you have a reference object. this is supposed to be a comment-- not allowing me to write.
Dec
11
answered Can modulus be negative?