meta user
network profile
| bio | website | |
|---|---|---|
| location | ||
| age | ||
| visits | member for | 6 months |
| seen | Mar 10 at 14:50 | |
| stats | profile views | 95 |
|
Dec 13 |
answered | Number of ways to choose k people from an alphabetized list of n people, with “gap” g |
|
Dec 13 |
comment |
Calculating the aspect ratio of the rotated rectangle on the image the credit card itself can be a reference. those cards come in standard size and thus ratio. |
|
Dec 12 |
answered | Draw a square around a point. |
|
Dec 12 |
comment |
Calculating the aspect ratio of the rotated rectangle on the image a reference that you know of the aspect ratio. eg. that of font printed on the card. |
|
Dec 11 |
comment |
A math teacher thought of a positive integer of two digits. wore me out. i took "divisors" differently-- outside its meaning. the idea is the number of divisors should be high enough that $2$ has to be one of them for the number be ( (even) & (less than $100$) ). |
|
Dec 11 |
comment |
Strong inducti0n with 3- and 5-peso notes and can pay any number greater than 7. this is an old Q. |
|
Dec 11 |
comment |
A math teacher thought of a positive integer of two digits. Still $6$ divisors BTW, not $7$. Those multiplied giving the number itself. Fell quick for your first comment. |
|
Dec 11 |
comment |
A math teacher thought of a positive integer of two digits. $96=2^5\times3$. Hanna can't chose between $96$ and $64$ by herself. |
|
Dec 11 |
revised |
A math teacher thought of a positive integer of two digits. added 89 characters in body |
|
Dec 11 |
comment |
A math teacher thought of a positive integer of two digits. Well, work it for 7 then. this is a solution. Thanks for the warning though. |
|
Dec 11 |
answered | A math teacher thought of a positive integer of two digits. |
|
Dec 11 |
comment |
Contrapositive of an Implication you sure about your resource ? |
|
Dec 11 |
revised |
Probability of choosing like partners added 729 characters in body |
|
Dec 11 |
awarded | Commentator |
|
Dec 11 |
comment |
Probability of choosing like partners yup, figured trying n works. Thx again. |
|
Dec 11 |
awarded | Custodian |
|
Dec 11 |
comment |
Probability of choosing like partners Thanks for the edit. how do you add the TeX markup in here though ? |
|
Dec 11 |
reviewed | Approve suggested edit on Probability of choosing like partners |
|
Dec 11 |
answered | Probability of choosing like partners |
|
Dec 11 |
revised |
Request theorem/Proof for $F(x)>0$ for $a<x<b$ added 12 characters in body |
