167 reputation
8
bio website
location Switzerland
age
visits member for 2 years, 1 month
seen Feb 4 at 8:12

Jun
26
awarded  Popular Question
Jan
21
comment 3rd grade math problem
My thoughts on this was that it doesn't really promote logical thinking but doing trial-and-error. I already told her that I consider that a really dumb problem. Thanks for the help, it shows to me there was no real "formula" to solve this, but to assume no carrying, and just go from there (granted that is something I didn't do when I tried to solve it)
Jan
21
accepted 3rd grade math problem
Jan
20
asked 3rd grade math problem
Dec
25
awarded  Student
Oct
4
comment “The Original IQ Test” — A peg puzzle
How can the genius solution even be achieved? In order to get a Peg in a one of those 8 holes, it needed to have been in one of the other 8 holes. Thus I feel like 7 pegs is the best solution you can achieve?
Oct
3
comment Riddle: 1 question to know if the number is 1, 2 or 3
@ChibuezeOpata The trick is to pose the question with a new random value the girl doesn't know, thus resulting in the "I don't know".
Sep
21
comment Percentage of an amount?
With Method 1 you are calculating 40% of the current pandas. Since those 6000 pandas represent 60% of the original, the 2400 are 40% of the 60%, so 24% of the original amount.
Sep
10
comment Blue eyes: a logic puzzle
But WHY doesn't brown eye leave after 100 days as well? Each islander sees at least 99 brown eyes, KNOWING that each of those knows that there are at least 98 brown eyes in the group? Every single brown eyed person knows that there are 99 or 100 brown eyes in the group, so that is common knowledge as well.
Aug
4
comment Is $83^{27} +1 $ a prime number?
@JeppeStigNielsen True, that slipped my mind...
Aug
3
awarded  Commentator
Aug
3
comment Is $83^{27} +1 $ a prime number?
@JeppeStigNielsen That doesn't make sense. $b^n+1$ can be a prime as well for n = 1, and b being a prime-1. So your comment cannot be entirely correct.
Jul
19
comment Easter Dates Different
It all depends on the accuracy needed. I feel like it will never work completely, since the rotational speeds of both earth and moon change, thus making every try obsolete in the first place.
Jul
19
comment Easter Dates Different
Note: leap years will be broken again after 3200 years. Thats the deal, you will have to live with a certain uncertainty, which basically screws this program. But writing a computer program to do this, no chance.
Jul
19
answered Easter Dates Different
Jul
19
comment Easter Dates Different
Basically it should be enough to show that an earth year (365.25 days) and moon revolution (27.32 days) do not line up, resulting in a shift. And thanks to leap years, the only valid answer would be something like 400, cause for everything else you break with leap years. Unfortunately, in 400 years, the 1/1 is not the same as 1/1 + 400, so it will just not happen. Every other number can be broken with leap years.
Jul
19
comment Solving a simple exponential equation
This is so much easier than the other solutions. Rather straight forward.
Jul
18
accepted Solve equation with variables inside and outside cos
Jul
18
comment Solve equation with variables inside and outside cos
Er, okay, I will refrain from trying to invent something, and instead do it numerically :)
Jul
18
asked Solve equation with variables inside and outside cos