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bio website mrcactu5.herokuapp.com/…
location New York, NY
age 29
visits member for 3 years, 3 months
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Data Scientist @ Explorer Media. Statistics, Geometry and Physics.

The infamous question... downvote to your heart's content:
Can Poisson Summation formula break? -12


Feb
15
comment asymptotics of $F_n = F_{k-1} F_{n-k-1} + F_{k-1} F_{n-k} + F_{k-2} F_{n-k} $
I took an existing Fibonacci identity and asked when $n,k >> 1$, what the asymptotics look like? It turns out $F_k \approx \frac{1}{\mathbf{\sqrt{5}}}\phi^k$ so and that $\frac{\phi^2 + 1}{\sqrt{5}}=\phi$.
Feb
15
revised asymptotics of $F_n = F_{k-1} F_{n-k-1} + F_{k-1} F_{n-k} + F_{k-2} F_{n-k} $
added 290 characters in body
Feb
15
comment asymptotics of $F_n = F_{k-1} F_{n-k-1} + F_{k-1} F_{n-k} + F_{k-2} F_{n-k} $
I tried writing $F_k F_{n-k} \approx \phi^n + \phi^{n-2k}$ still doesn't work.
Feb
15
asked asymptotics of $F_n = F_{k-1} F_{n-k-1} + F_{k-1} F_{n-k} + F_{k-2} F_{n-k} $
Feb
15
answered 2 states, 2 interarrival distribution Renewal Process.
Feb
15
comment 2 states, 2 interarrival distribution Renewal Process.
What do you think is meant by "the usual convolutions"?
Feb
15
asked uniform spanning tree of $2 \times n$ graph
Feb
15
reviewed Approve suggested edit on 2 states, 2 interarrival distribution Renewal Process.
Feb
11
reviewed Approve suggested edit on Determining a polynomial
Feb
10
reviewed Approve suggested edit on Solve $y = 8x^{-0.45}$ in terms of $x$?
Feb
10
comment Could $4+2+4+2+4+2+\cdots = -1 $?
oh what a great video! i will show to my friends!
Feb
10
asked Could $4+2+4+2+4+2+\cdots = -1 $?
Feb
10
reviewed Approve suggested edit on One to One Correspondence between the Set of All functions
Feb
10
comment two brownian motions in $ \mathbb{Z}^2 $
I get that... $\frac{1}{2}(\cos u + \cos v) = \frac{1}{4}(e^{iu}+ e^{iv} + e^{-iu} + e^{-iv})$ like a transfer operator. So you are taking the $(0,0)$ Fourier coefficient of $$\frac{1}{4}(e^{iu}+ e^{iv} + e^{-iu} + e^{-iv})$$
Feb
9
asked Alternative coordinates for the complex plane $\mathrm{Re}[e^{-is}z]=a$, $\mathrm{Re}[e^{-it}z]=b $
Feb
9
reviewed Approve suggested edit on How to work out this integral
Feb
9
reviewed Approve suggested edit on How to work out this integral
Feb
9
comment two brownian motions in $ \mathbb{Z}^2 $
I don't know then. What if your steps were $(\pm 1, \pm 1)$ instead of $(\pm 1,0), (0,\pm 1)$ ? Why don't you edit the question and write a clearer definition of 2D random walk? It should be clear enough that we can decide if moving in the x and y directions are independent.
Feb
9
comment two brownian motions in $ \mathbb{Z}^2 $
Yes it is strange. However, for random walks in the plane the x and y directions are independent. mathworld.wolfram.com/RandomWalk2-Dimensional.html You can still use Pascal's triangle to find out when $\mathbb{P}(Y_1 - Y_2) = 0$. Instead it is $\binom{2n}{n-2}$
Feb
9
answered two brownian motions in $ \mathbb{Z}^2 $