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Jul
6
revised Does $ \sum_{(m,n) \neq (0,0)} \frac{(-1)^{m+n}}{m^2 + n^2} $ have an exact value?
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Jul
6
revised Does $ \sum_{(m,n) \neq (0,0)} \frac{(-1)^{m+n}}{m^2 + n^2} $ have an exact value?
added 233 characters in body
Jul
6
revised Does $ \sum_{(m,n) \neq (0,0)} \frac{(-1)^{m+n}}{m^2 + n^2} $ have an exact value?
added 567 characters in body
Jul
6
revised Does $ \sum_{(m,n) \neq (0,0)} \frac{(-1)^{m+n}}{m^2 + n^2} $ have an exact value?
added 567 characters in body
Jul
6
revised Does $ \sum_{(m,n) \neq (0,0)} \frac{(-1)^{m+n}}{m^2 + n^2} $ have an exact value?
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Jul
6
asked Does $ \sum_{(m,n) \neq (0,0)} \frac{(-1)^{m+n}}{m^2 + n^2} $ have an exact value?
Jul
6
revised Sum: $1-2+3-4+5-6+…$
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Jul
6
answered Sum: $1-2+3-4+5-6+…$
Jul
6
revised Extending 2-adic valuation to real numbers
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Jul
6
revised Extending 2-adic valuation to real numbers
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Jul
6
revised Extending 2-adic valuation to real numbers
added 238 characters in body
Jul
6
revised Extending 2-adic valuation to real numbers
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Jul
6
answered Extending 2-adic valuation to real numbers
Jun
29
revised Is there something between summation and integration?
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Jun
29
comment Is there something between summation and integration?
this is answering a very different question actually, but it might be of interest
Jun
29
answered Is there something between summation and integration?
Jun
28
comment How to derive $\sum_{n=0}^\infty 1 = -\frac{1}{2}$ without zeta regularization
@AsafKaragila I specify this was done with zeta function regularization. Would it be more precise to ask for the analytic continuation $\zeta(0)$ ?
Jun
28
comment How to derive $\sum_{n=0}^\infty 1 = -\frac{1}{2}$ without zeta regularization
Could you prove Ramanujan summation as Euler-Maclaurin to 1st order?
Jun
28
comment How to derive $\sum_{n=0}^\infty 1 = -\frac{1}{2}$ without zeta regularization
hmm? that seems plausible that $\sum (0+2) = \sum (1+1)$ and yet $\sum (0+2) = 2 \sum 1$.
Jun
28
comment How to derive $\sum_{n=0}^\infty 1 = -\frac{1}{2}$ without zeta regularization
@AsafKaragila this false statement has its own wikipedia article