4,941 reputation
618
bio website mrcactu5.herokuapp.com/…
location New York, NY
age 29
visits member for 3 years, 7 months
seen 11 hours ago

Data Scientist @ Explorer Media


May
8
answered $|z_{1}- z_{2}| \leq |w_{1}- w_{2}| \implies |c_{1}z_{1}- c_{2}z_{2}| \leq |c_{1}w_{1}- c_{2} w_{2}|$?
May
7
revised Proof of “Japanese Theorem” — Triangulation of Cyclic Polygon
added 7 characters in body
May
5
comment How prove $|S-10^k\cdot AB|\le 9k$
@CalvinLin It looked interesting. I have attempted to salvage the problem. Please see if my edit is correct.
May
5
revised How prove $|S-10^k\cdot AB|\le 9k$
added 29 characters in body; edited tags
May
5
comment Proof of “Japanese Theorem” — Triangulation of Cyclic Polygon
@MaMing Ok, so insides cancel? And we get $(\# \text{sides} ) \times (\text{circumradius}) + \sum_\Delta (\text{inradus} ) = \sum \overline{OA}_i$. We still have to prove Carnot's result. Maybe using Barycentric coordinates?
May
5
revised Proof of “Japanese Theorem” — Triangulation of Cyclic Polygon
added 19 characters in body
May
5
revised Proof of “Japanese Theorem” — Triangulation of Cyclic Polygon
added 19 characters in body
May
5
asked Proof of “Japanese Theorem” — Triangulation of Cyclic Polygon
May
4
reviewed Approve suggested edit on Volume of a square pyramid— what's wrong in my analysis
May
3
comment Is there a base in which $1 + 2 + 3 + 4 + \dots = - \frac{1}{12}$ makes sense?
@MarianoSuárez-Alvarez That's why I mention the p-adic numbers where a number like $\dots5$ makes sense. Here $10$ is composite so there may not be 10-adic numbers, if you like, replace it with $7$.
May
3
asked Is there a base in which $1 + 2 + 3 + 4 + \dots = - \frac{1}{12}$ makes sense?
May
2
comment Probabilistic proof that $\sum \binom{n}{k}^{-1} > \frac{n}{2^n}$
Assuming this IMO problem and $\boxed{2^k > k^2}$ we can (im)prove the bound, yes :-)
May
2
comment Probabilistic proof that $\sum \binom{n}{k}^{-1} > \frac{n}{2^n}$
Is that equality ? The link is United States TST 2000
May
1
revised How prove this inequality $\sum_{k=1}^{n}\frac{2k-1}{k\binom{n}{k}}\ge \frac{n}{2^{n-1}}$
added 92 characters in body
May
1
reviewed Approve suggested edit on submodular-like functions on $\mathbb{R}$
May
1
revised How prove this inequality $\sum_{k=1}^{n}\frac{2k-1}{k\binom{n}{k}}\ge \frac{n}{2^{n-1}}$
improved estimate
May
1
revised How prove this inequality $\sum_{k=1}^{n}\frac{2k-1}{k\binom{n}{k}}\ge \frac{n}{2^{n-1}}$
improved estimate
May
1
answered How prove this inequality $\sum_{k=1}^{n}\frac{2k-1}{k\binom{n}{k}}\ge \frac{n}{2^{n-1}}$
May
1
comment Intersection between sphere and ellipsoid
Scicomp.Stackexchange.com
May
1
revised Probabilistic proof that $\sum \binom{n}{k}^{-1} > \frac{n}{2^n}$
added 194 characters in body; added 57 characters in body; added 2 characters in body