john mangual
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 May 26 revised Can we find the 18 imaginary quadratic ffields with class number 2 algorithmically? added 356 characters in body; edited title May 26 asked Can we find the 18 imaginary quadratic ffields with class number 2 algorithmically? May 24 revised Without using Heegner-Stark-Baker, $\mathbb{Q}(\sqrt{-11})$ has class number $1$. Introductory text May 23 comment Prove that $\gcd(a^n - 1, a^m - 1) = a^{\gcd(n, m)} - 1$ Sort of like the Fibonacci sequence! May 22 revised Enumerating Bianchi circles added 375 characters in body May 22 answered Enumerating Bianchi circles May 22 comment Without using Heegner-Stark-Baker, $\mathbb{Q}(\sqrt{-11})$ has class number $1$. math.stackexchange.com/questions/957224/… May 22 comment Without using Heegner-Stark-Baker, $\mathbb{Q}(\sqrt{-11})$ has class number $1$. See Master's Thesis of Abebe Simachew (Ethiopia / Boreaux) A Survey of Euclidean Number Fields May 22 revised Without using Heegner-Stark-Baker, $\mathbb{Q}(\sqrt{-11})$ has class number $1$. demonstrate no longer true for Zsqrt19 May 22 revised how to parameterize the ellipse $x^2 + xy + 3y^2 = 1$ with $\sin \theta$ and $\cos \theta$ added 522 characters in body May 22 asked how to parameterize the ellipse $x^2 + xy + 3y^2 = 1$ with $\sin \theta$ and $\cos \theta$ May 21 revised Without using Heegner-Stark-Baker, $\mathbb{Q}(\sqrt{-11})$ has class number $1$. deleted 7 characters in body May 21 revised Without using Heegner-Stark-Baker, $\mathbb{Q}(\sqrt{-11})$ has class number $1$. added 35 characters in body May 21 answered Without using Heegner-Stark-Baker, $\mathbb{Q}(\sqrt{-11})$ has class number $1$. May 21 revised Concatenating countably many homotopies added 115 characters in body May 21 revised Concatenating countably many homotopies added 434 characters in body May 21 answered Concatenating countably many homotopies May 21 revised Cauchy-Ramanujan Formula $\displaystyle \sum_{\stackrel{m \in \mathbb{Z}}{m \neq 0}} \frac{\coth m \pi}{m^{4p+3}}$ added 17 characters in body May 21 asked Cauchy-Ramanujan Formula $\displaystyle \sum_{\stackrel{m \in \mathbb{Z}}{m \neq 0}} \frac{\coth m \pi}{m^{4p+3}}$ May 21 revised Visualizing Euclidean Algorithm in $\mathbb{Q}(\sqrt{-7})$ and $\mathbb{Q}(\sqrt{-11})$ with Convex Geometry deleted 20 characters in body