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May
26
revised Can we find the 18 imaginary quadratic ffields with class number 2 algorithmically?
added 356 characters in body; edited title
May
26
asked Can we find the 18 imaginary quadratic ffields with class number 2 algorithmically?
May
24
revised Without using Heegner-Stark-Baker, $\mathbb{Q}(\sqrt{-11})$ has class number $1$.
Introductory text
May
23
comment Prove that $\gcd(a^n - 1, a^m - 1) = a^{\gcd(n, m)} - 1$
Sort of like the Fibonacci sequence!
May
22
revised Enumerating Bianchi circles
added 375 characters in body
May
22
answered Enumerating Bianchi circles
May
22
comment Without using Heegner-Stark-Baker, $\mathbb{Q}(\sqrt{-11})$ has class number $1$.
math.stackexchange.com/questions/957224/…
May
22
comment Without using Heegner-Stark-Baker, $\mathbb{Q}(\sqrt{-11})$ has class number $1$.
See Master's Thesis of Abebe Simachew (Ethiopia / Boreaux) A Survey of Euclidean Number Fields
May
22
revised Without using Heegner-Stark-Baker, $\mathbb{Q}(\sqrt{-11})$ has class number $1$.
demonstrate no longer true for Zsqrt19
May
22
revised how to parameterize the ellipse $x^2 + xy + 3y^2 = 1$ with $\sin \theta$ and $\cos \theta$
added 522 characters in body
May
22
asked how to parameterize the ellipse $x^2 + xy + 3y^2 = 1$ with $\sin \theta$ and $\cos \theta$
May
21
revised Without using Heegner-Stark-Baker, $\mathbb{Q}(\sqrt{-11})$ has class number $1$.
deleted 7 characters in body
May
21
revised Without using Heegner-Stark-Baker, $\mathbb{Q}(\sqrt{-11})$ has class number $1$.
added 35 characters in body
May
21
answered Without using Heegner-Stark-Baker, $\mathbb{Q}(\sqrt{-11})$ has class number $1$.
May
21
revised Concatenating countably many homotopies
added 115 characters in body
May
21
revised Concatenating countably many homotopies
added 434 characters in body
May
21
answered Concatenating countably many homotopies
May
21
revised Cauchy-Ramanujan Formula $ \displaystyle \sum_{\stackrel{m \in \mathbb{Z}}{m \neq 0}} \frac{\coth m \pi}{m^{4p+3}} $
added 17 characters in body
May
21
asked Cauchy-Ramanujan Formula $ \displaystyle \sum_{\stackrel{m \in \mathbb{Z}}{m \neq 0}} \frac{\coth m \pi}{m^{4p+3}} $
May
21
revised Visualizing Euclidean Algorithm in $\mathbb{Q}(\sqrt{-7})$ and $\mathbb{Q}(\sqrt{-11})$ with Convex Geometry
deleted 20 characters in body