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accepted Computing the intersection of two arithmetic sequences $(a\mathbb{Z} + b) \cap (c \mathbb{Z} + d)$
1h
asked Computing the intersection of two arithmetic sequences $(a\mathbb{Z} + b) \cap (c \mathbb{Z} + d)$
20h
accepted Can the numbers $2^m 3^n$ have an infinitely long arithmetic sequence?
1d
comment Can the numbers $2^m 3^n$ have an infinitely long arithmetic sequence?
See it's not so easy? Dirichlet's theorem was my motivation for this problem. As for the comments above, proving the natural density is 0 might also be hard.
1d
asked Can the numbers $2^m 3^n$ have an infinitely long arithmetic sequence?
1d
revised If $p$ is a prime number and $p\equiv 1(mod 4)$, (show that) there exist integers $a$ and $b$ such that $a^{2}+b^{2}=p$.
added 48 characters in body
Jul
25
comment Can $O(\sqrt{x})$ be considered $o(x)$?
@user251257 Oh my. What an important question. I guess $\boxed{x \to \infty}$, but $x \to 0$ could be important.
Jul
25
revised Can $O(\sqrt{x})$ be considered $o(x)$?
added 179 characters in body
Jul
25
asked Can $O(\sqrt{x})$ be considered $o(x)$?
Jul
19
comment Product of complex numbers $m+in$ with $0 < m,n \leq N$
@zardo if you can find Stirling approximation in that case then please write an answer
Jul
19
asked Product of complex numbers $m+in$ with $0 < m,n \leq N$
Jul
18
comment Explaining Mathematical Modelling to a nonmathematician
have you considered Math Educators Stackexchange
Jul
18
answered determining which cyclotomic polynomial is $x^8 -x^4+1$
Jul
16
revised If $p\equiv1\pmod{4}$ is a prime, then $-4$ and $(p-1)/4$ are both quadratic residues of $p$.
added 257 characters in body
Jul
16
answered If $p\equiv1\pmod{4}$ is a prime, then $-4$ and $(p-1)/4$ are both quadratic residues of $p$.
Jul
10
revised Let $A \subset \mathbb Z^3$ / $|A| < \infty$. Prove that: $|A| \le \sqrt{|A_x| |A_y| |A_z|}$
added 14 characters in body
Jul
10
revised How prove this inequality $(1+\frac{1}{16})^{16}<\frac{8}{3}$
added 387 characters in body
Jul
9
comment How prove this inequality $(1+\frac{1}{16})^{16}<\frac{8}{3}$
@StevenStadnicki thanks I redid it from scratch
Jul
9
revised How prove this inequality $(1+\frac{1}{16})^{16}<\frac{8}{3}$
deleted 404 characters in body
Jul
9
revised How prove this inequality $(1+\frac{1}{16})^{16}<\frac{8}{3}$
edited body