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bio website mrcactu5.herokuapp.com/…
location New York, NY
age 29
visits member for 3 years, 10 months
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Data Scientist @ Explorer Media


1d
asked What does “of independent interest” mean in math papers?
Oct
27
revised Using Dirichlet's hyperbola method and Dirichlet's formula
reading the photograph and substantial cleaning up of text
Oct
27
revised crazy number of divisors chart on Wikipedia - $\Omega(n)$
added 467 characters in body; edited title
Oct
27
revised crazy number of divisors chart on Wikipedia - $\Omega(n)$
added 467 characters in body; edited title
Oct
27
revised crazy number of divisors chart on Wikipedia - $\Omega(n)$
added 467 characters in body; edited title
Oct
27
asked crazy number of divisors chart on Wikipedia - $\Omega(n)$
Oct
17
revised Nice derivation of $\sum_{n=1}^\infty \frac{1}{n} \left( \frac{q^{2n}}{1-q^n}+\frac{\bar q^{2n}}{1-\bar q^n}\right)=-\sum_{m=2}^\infty \ln |1-q^m|^2$
added 2 characters in body
Oct
15
revised Nice derivation of $\sum_{n=1}^\infty \frac{1}{n} \left( \frac{q^{2n}}{1-q^n}+\frac{\bar q^{2n}}{1-\bar q^n}\right)=-\sum_{m=2}^\infty \ln |1-q^m|^2$
forgot an important sum sign
Oct
15
revised Nice derivation of $\sum_{n=1}^\infty \frac{1}{n} \left( \frac{q^{2n}}{1-q^n}+\frac{\bar q^{2n}}{1-\bar q^n}\right)=-\sum_{m=2}^\infty \ln |1-q^m|^2$
connection to Virsasoro
Oct
15
revised Nice derivation of $\sum_{n=1}^\infty \frac{1}{n} \left( \frac{q^{2n}}{1-q^n}+\frac{\bar q^{2n}}{1-\bar q^n}\right)=-\sum_{m=2}^\infty \ln |1-q^m|^2$
connection to Virsasoro
Oct
15
answered Nice derivation of $\sum_{n=1}^\infty \frac{1}{n} \left( \frac{q^{2n}}{1-q^n}+\frac{\bar q^{2n}}{1-\bar q^n}\right)=-\sum_{m=2}^\infty \ln |1-q^m|^2$
Oct
14
comment Correctly transforming ODEs
@resu I was going to suggest $y+1 \mapsto y$ for the first step. Where did these equations come from? What text?
Oct
13
comment What is the value of $\sum_{m=1}^{19} \frac{1}{\zeta^{3m}+\zeta^{2m}+\zeta^{m}+1}$ with $\zeta=e^{2\pi i/19}$?
line 3 is very convenient that $x \mapsto x^k$ is the same as rearranging the terms
Oct
13
comment What is the value of $\sum_{m=1}^{19} \frac{1}{\zeta^{3m}+\zeta^{2m}+\zeta^{m}+1}$ with $\zeta=e^{2\pi i/19}$?
this is good you can use polynmial identity summing over the roots: $$ \frac{d}{dz} \big[\log p(z)\big]= \frac{p'(z)}{p(z)} = \sum \frac{1}{z-a} $$ where $p(z) = z^N-1$.
Oct
13
comment Show Laplace operator is rotationally invariant
@EmutheEmu By chain rule, your equation $u = x \cos \theta + y \sin \theta$ becomes $$\frac{\partial}{\partial u} = \frac{\partial}{\partial x} \cos \theta + \frac{\partial}{\partial y} \sin \theta $$ and a similar formula for second derivatives. Then you can plug in.
Oct
13
revised Show Laplace operator is rotationally invariant
added 643 characters in body
Oct
12
answered Show Laplace operator is rotationally invariant
Oct
12
revised Proving that $\sum \overline{PV_i}^2=\frac{nl^2}{4}\left(1+2\cot^2 \frac{\pi}{n}\right)$
added 226 characters in body
Oct
12
revised Proving that $\sum \overline{PV_i}^2=\frac{nl^2}{4}\left(1+2\cot^2 \frac{\pi}{n}\right)$
added 226 characters in body
Oct
12
revised Proving that $\sum \overline{PV_i}^2=\frac{nl^2}{4}\left(1+2\cot^2 \frac{\pi}{n}\right)$
added 226 characters in body