Reputation
514
Top tag
Next privilege 1,000 Rep.
Create new tags
Badges
3 19
Impact
~16k people reached

  • 0 posts edited
  • 1 helpful flag
  • 40 votes cast
May
24
awarded  Popular Question
Feb
21
awarded  Popular Question
Jan
24
awarded  Tumbleweed
Dec
27
awarded  Popular Question
Dec
9
awarded  Caucus
Nov
18
awarded  Yearling
Sep
24
awarded  Autobiographer
Jul
2
awarded  Curious
Jul
2
awarded  Inquisitive
May
31
comment Prove $\lim_{n \to \infty} \frac{\Gamma(n+1/2)}{\Gamma(n)~n^{1/2}}=1$
I got $\lim_{x \to \infty}(1+a/x)^{x+a-1/2}*e^{-a}=1$, right?
May
31
comment Prove $\lim_{n \to \infty} \frac{\Gamma(n+1/2)}{\Gamma(n)~n^{1/2}}=1$
excellent, thank you. didn't think about using the Stirling's formula in the way you showed. now I know, thanks again!
May
31
accepted Prove $\lim_{n \to \infty} \frac{\Gamma(n+1/2)}{\Gamma(n)~n^{1/2}}=1$
May
31
asked Prove $\lim_{n \to \infty} \frac{\Gamma(n+1/2)}{\Gamma(n)~n^{1/2}}=1$
Nov
18
awarded  Yearling
Aug
3
asked What is the quotient of a cyclic group of order $n$ by a cyclic subgroup of order $m$?
Aug
3
accepted Quotient group - explanation over explanation
Aug
3
comment Quotient group - explanation over explanation
that's what I thought, though I couldn't make the difference, because I dissected both into elements. thanks!
Aug
3
revised Quotient group - explanation over explanation
deleted 9 characters in body
Aug
3
asked Quotient group - explanation over explanation
Jul
27
asked If $k$ divides $n$ then there's only one subgroup of $G$ of order $k$