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location Kolkata, India
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seen Oct 16 at 14:19

Nov
15
awarded  Yearling
Feb
2
awarded  Nice Answer
Nov
20
answered A version of existence and uniqueness of solution for an initival value problem of ODE
Nov
19
answered If f is in LipK[a, b], show that f can be uniformly approximated by polynomials in LipK[ a, b].
Nov
19
revised Inverse estimate of gradient of Sobolev function
added 14 characters in body
Nov
19
answered Inverse estimate of gradient of Sobolev function
Nov
19
revised Proof of an inequality of $L^p$ norms
added 232 characters in body
Nov
19
revised Proof of an inequality of $L^p$ norms
added 323 characters in body
Nov
19
revised Proof of an inequality of $L^p$ norms
added 323 characters in body
Nov
19
answered Proof of an inequality of $L^p$ norms
Nov
19
comment Quasiconvex and quasiconcave graphs
There are several definitions of quasiconvexity in the literature. Could you please tell us which one you are referring to?
Nov
18
answered Convergence of an improper integral - II
Nov
18
comment Is every connected metric space with at least two points uncountable?
Yes, you are right. Since the problem was posed for a metric space, instead of invoking the Urysohn Lemma, I constructed a Urysohn function explicitly.
Nov
18
comment Inequality involving a sequence in Hilbert space
weak lower semicontinuity of norm will not give you the result?
Nov
18
awarded  Commentator
Nov
18
comment Find the sum of the first $n$ terms of $\sum^n_{k=1}k^3$
Please consider the special case n=4 and try to see where you are going wrong.
Nov
18
comment Wedge product with a non-degenerate form
What you are asking is essentially related to the notion of exterior annihilators and divisibility. You may refer to the book "The Pullback Equation for Differential Forms" by Csato-Dacorogna-Kneuss for more information in this direction.
Nov
18
answered Wedge product with a non-degenerate form
Nov
18
comment Is every connected metric space with at least two points uncountable?
That $f(X)=[0,1]$ follows from the fact that X is connected.
Nov
18
comment Maximal vs upper bound in a POSET
for every $x\in A$...... This implies that $A$ is singleton which is a contradiction.