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Jan
30
asked highest weight of adjoint represesentation
Jan
5
comment Lie algebras over non-algebraically closed field
@MarianoSuárez-Alvarez Very well then. I'll try and get used to Bourbaki this semester. But I recently found Hilgert and Neeb's Structure and Geometry of Lie Groups and it's also what I'm looking for.
Jan
5
asked Lie algebras over non-algebraically closed field
Jan
1
accepted Hopf algebras and “unifying” representation theory
Dec
14
accepted Vectors fixed under compact subgroup
Nov
22
awarded  Popular Question
Nov
14
awarded  Yearling
Nov
9
awarded  Nice Question
Oct
31
asked Hopf algebras and “unifying” representation theory
Oct
18
comment Haar measure on $\mathbb{C} \setminus 0$.
@ThomasAndrews Don't you mean $S^1 \times \mathbb{R}^{+}$? That's what I had in my post. Unless your isomorphism is true as well and is more useful somehow.
Oct
18
asked Haar measure on $\mathbb{C} \setminus 0$.
Oct
17
accepted Peter-Weyl theorem versions
Oct
15
accepted Weights of $\mathfrak{sl}_2(\mathbb{C})$ representation
Oct
14
comment MATH PROBLEMS THIRD GRADE
pauli.uni-muenster.de/~munsteg/arnold.html "To the question "what is 2 + 3" a French primary school pupil replied: "3 + 2, since addition is commutative". He did not know what the sum was equal to and could not even understand what he was asked about!"
Oct
14
comment Peter-Weyl theorem versions
I greatly appreciate that you typed this out for me. However, I was thinking there would be a shorter argument, and one which had a more analytic than Lie-Theoretic feel.
Oct
14
comment Peter-Weyl theorem versions
@JohnMa I just want the group to satisfy whatever conditions the Peter-Weyl theorems require.
Oct
14
comment Peter-Weyl theorem versions
Sure. I don't think it matters to much at the end of the day.
Oct
14
asked Peter-Weyl theorem versions
Oct
13
comment Vectors fixed under compact subgroup
Let us continue this discussion in chat.
Oct
13
comment Vectors fixed under compact subgroup
It's the circle group, which is abelian... perhaps characters somehow come into play here. Sorry, I am really guessing.