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Financial mathematician-beginner.


37m
awarded  Tumbleweed
Sep
25
revised Extrema of a functional simple question
added 13 characters in body
Sep
25
asked Extrema of a functional simple question
Sep
24
awarded  Autobiographer
Sep
23
accepted Switching $\int$ and $\sum$ proof
Sep
23
comment Switching $\int$ and $\sum$ proof
Ah and as we know integral is linear so it could also be expressed as a (finite) sum of integrals right?
Sep
23
asked Switching $\int$ and $\sum$ proof
Sep
23
comment Rational function inequality
Added that aswell
Sep
23
revised Rational function inequality
added 44 characters in body
Sep
23
revised Rational function inequality
added 60 characters in body
Sep
23
comment Rational function inequality
Ah right, sorry. Polynomials, I'l add that.
Sep
23
asked Rational function inequality
Sep
21
accepted Limit Point of Zero Points Implying a Zero Function
Sep
21
comment Limit Point of Zero Points Implying a Zero Function
Thanks. This has got to be it. Which brings me to the question why am I not aware of that. Is that perhaps a corollary of some more "famous" theorem?
Sep
21
revised Limit Point of Zero Points Implying a Zero Function
added 11 characters in body
Sep
21
asked Limit Point of Zero Points Implying a Zero Function
Sep
19
accepted Euler-Lagrange equation: Differentiation with respect to x
Sep
19
asked Euler-Lagrange equation: Differentiation with respect to x
Sep
19
comment Strong and weak extrema
I feel like I follow and agree with everything you wrote. But it is exactly this that confuses me. When we add the stronger condition $P'$, we, as you noted, we eliminate some functions. Take a function that we eliminate. This function would then be within the neighborhood of the strong extrema, but not the weak one. How does that then imply the implication strong $\implies$ weak? In other words, it seems as if the weak extremum is "more of an extremum" than the strong one.
Sep
18
asked Strong and weak extrema