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Mar
13
revised Replace $n$ sets with two sets (set theoretic equality)
small error fixes
Mar
13
suggested approved edit on Replace $n$ sets with two sets (set theoretic equality)
Mar
13
comment Replace $n$ sets with two sets (set theoretic equality)
@Unwisdom: I mean $\bigcup_{j\neq i}A_{j}$. (It can't mean something different.)
Mar
13
revised Replace $n$ sets with two sets (set theoretic equality)
deleted 11 characters in body
Mar
13
asked Replace $n$ sets with two sets (set theoretic equality)
Mar
8
revised A totally bounded uniformity and certain filters
added 2 characters in body
Mar
8
comment A totally bounded uniformity and certain filters
Oops, I've corrected an error in the second displayed formula (and yet one more error in the same formula)
Mar
8
revised A totally bounded uniformity and certain filters
added 2 characters in body
Mar
8
asked A totally bounded uniformity and certain filters
Mar
8
comment A stronger concept than total boundness
Hm, it means I err saying that for a space to by totally bounded it's enough for every proper principal filter to be refined by a Cauchy filter. (I can't find a reference where have I got this statement about principal filters from. Maybe, I've just confused principal and proper filter.)
Mar
8
comment A stronger concept than total boundness
It seems from ncatlab.org/nlab/show/precompact+space that "totally bounded" and "precompact" are the same. But I need a proof of this
Mar
8
answered A stronger concept than total boundness
Mar
8
asked A stronger concept than total boundness
Mar
6
accepted Different uniform spaces having the same set of Cauchy filters
Mar
6
asked Different uniform spaces having the same set of Cauchy filters
Mar
6
comment Union of Cartesian squares
If I take $X_i=\{a,b\}$ then $X_i\times X_i = \{ (a,a), (a,b), (b,a), (b,b) \}$ and thus I see no any reason for $X_i\times X_i \subseteq R$.
Mar
6
asked Union of Cartesian squares
Mar
2
asked Is there a specific term for such collections of filters?
Mar
1
awarded  Organizer
Feb
28
comment Cauchy filters defined for proximity spaces?
Hm... maybe all proximity spaces are totally bounded? We need examples or counter-examples