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 Yearling
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Feb
2
comment Circle is similar to a polygon with infinite number of sides
@Kaster And I prefer it to be considered not as a limit, but as a "real" polygon with infinite number of sides. For example in complex number theory the infinity is not just a limit of finite values, but a quite particular point of Riemann sphere.
Feb
2
comment Circle is similar to a polygon with infinite number of sides
@Kaster I know that it is a limit. But what is the topology and what is the filter on which the limit is taken?
Feb
2
asked Circle is similar to a polygon with infinite number of sides
Jan
9
asked A property of product order
Dec
17
awarded  Yearling
Nov
20
comment Name of the class of maps between posets such that $f(x)\le f(y)\implies x\le y$
Oh, if the implication holds also in the reverse direction, it is an order embedding. This is probably what I need
Nov
19
revised Name of the class of maps between posets such that $f(x)\le f(y)\implies x\le y$
edited title
Nov
19
asked Name of the class of maps between posets such that $f(x)\le f(y)\implies x\le y$
Oct
12
awarded  Informed
Oct
12
revised Embed boolean lattice into complete atomic boolean lattice
added 40 characters in body
Oct
12
asked Embed boolean lattice into complete atomic boolean lattice
Oct
11
awarded  Civic Duty
Oct
11
accepted Intersection of two filters on a poset
Oct
10
accepted Locally monotone function is monotone
Oct
10
comment Locally monotone function is monotone
I don't get why $I$ must be a $\sim$-class
Oct
10
revised Locally monotone function is monotone
added 77 characters in body
Oct
10
comment I don't understand why we represent functions $f:I \subseteq \Bbb R \to \Bbb R^2$ the way we do.
Also note that for 1-argument functions the image is usually just an interval on the real line, not an interesting set. For this reason interesting images (such as parametric curves) usually appear for 2-argument (or more arguments) functions. This was the exact reason of your confusion, when you switched from 1-argument to 2-argument functions
Oct
10
answered I don't understand why we represent functions $f:I \subseteq \Bbb R \to \Bbb R^2$ the way we do.
Oct
10
asked Locally monotone function is monotone
Oct
9
answered Another conjecture about $C^1$ integral curves