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 Apr6 revised Prove that $\frac{f(n)+a}{g(n)+b} = O(\frac{f(n)}{g(n)})$ added 127 characters in body Apr6 asked Prove that $\frac{f(n)+a}{g(n)+b} = O(\frac{f(n)}{g(n)})$ Jan10 comment Notation of functions Could you please explain more about this? Why would anyone need to do this? Perhaps you could provide a link to some reference? Also, could you explain the usage of "|" symbol in definition? What does it signify? Or is it interchangeable with ","? Jan10 asked Notation of functions Nov4 awarded Yearling Jul2 awarded Curious Jun13 comment Sum of normally distributed random variables Thanks, I didn't think about this Jun13 asked Sum of normally distributed random variables Jun12 comment Bernoulli trials are run until 3 successful trials are completed. If probability of a success is 0.3 what is the expected number of failures? Binomial distribution: E[X] = np, if E[X] = 3 and p = 0.3 we get n=10 and the number of failures is 10-3=7. Isn't it strange that this gives the same answer even if this is not in binomial distribution (as far as I understand)? Jun12 comment Bernoulli trials are run until 3 successful trials are completed. If probability of a success is 0.3 what is the expected number of failures? But I am aware of Pascal's distribution which looks similar to NB. Using that I get that E[x]=n*0.3/0.7 = 3 => n=7. So the number of failures is 7-3=4? Jun12 comment Bernoulli trials are run until 3 successful trials are completed. If probability of a success is 0.3 what is the expected number of failures? @Studentmath no, I am not Jun12 asked Bernoulli trials are run until 3 successful trials are completed. If probability of a success is 0.3 what is the expected number of failures? Jun11 asked Probability of event happening in Bernoulli scheme if most likely outcome is given? Jun10 asked What events should be added for it to become sigma algebra? Jun10 accepted 5 cards are drawn. Probability of second or third card being diamonds. Jun10 comment 5 cards are drawn. Probability of second or third card being diamonds. So, if I understand correctly, then the answer simply is 1 - (39*38)/(52*51) ? Jun10 asked 5 cards are drawn. Probability of second or third card being diamonds. May13 asked Random variable and CDF Mar7 awarded Notable Question Mar6 accepted Continuous probability. Angles