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| bio | website | |
|---|---|---|
| location | ||
| age | 18 | |
| visits | member for | 6 months |
| seen | Mar 25 at 12:45 | |
| stats | profile views | 37 |
Just started first year in Computer Science, Which means I have mostly math courses: Calculus 1, Linear Algebra 1 and Discrete math.
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Dec 5 |
accepted | $\mathbb{R}\subset\mathbb{F}\subset\mathbb{C}$ implies $\mathbb{F}=\mathbb{R}$ or $\mathbb{F}=\mathbb{C}$? |
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Dec 5 |
comment |
$\mathbb{R}\subset\mathbb{F}\subset\mathbb{C}$ implies $\mathbb{F}=\mathbb{R}$ or $\mathbb{F}=\mathbb{C}$? Oh yeah... You reminded me that we did prove that fields are vector spaces above subfields of themselves. This really does make it a lot simpler. Thank you! |
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Dec 5 |
asked | $\mathbb{R}\subset\mathbb{F}\subset\mathbb{C}$ implies $\mathbb{F}=\mathbb{R}$ or $\mathbb{F}=\mathbb{C}$? |
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Dec 1 |
awarded | Enthusiast |
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Nov 28 |
comment |
$a_{n+1}=\frac{1}{4}+a_n^2$ is converging and have a limit Thank you! That's a nice trick i didn't know... Too bad classes here doesn't bother to teach you how to solve the exercises you get... |
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Nov 28 |
accepted | $a_{n+1}=\frac{1}{4}+a_n^2$ is converging and have a limit |
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Nov 28 |
asked | $a_{n+1}=\frac{1}{4}+a_n^2$ is converging and have a limit |
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Nov 25 |
revised |
Proving that if $a_n\in\mathbb{Z}$ for all $n$ then it's limit is also in $\mathbb{Z}$? added 224 characters in body |
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Nov 25 |
asked | Proving that if $a_n\in\mathbb{Z}$ for all $n$ then it's limit is also in $\mathbb{Z}$? |
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Nov 21 |
comment |
Proving $0$ is the limit of $\frac{n}{2^n-1}$ from definition alone Well, the second way is pretty similar to Pambos's idea, but I really don't feel comfortable with logs. Is it something you expect I'd be introduced to or should I make an effort learn it on my own? |
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Nov 21 |
accepted | Proving $0$ is the limit of $\frac{n}{2^n-1}$ from definition alone |
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Nov 21 |
comment |
Proving a vector space over itself have no subspaces In the end, after actually understanding how to use the dimensions, I found the other way simpler. But thanks for the help! |
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Nov 21 |
accepted | Proving a vector space over itself have no subspaces |
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Nov 20 |
comment |
Proving $0$ is the limit of $\frac{n}{2^n-1}$ from definition alone Both answers say to use logs, but as of now we never had to use stuff that wasn't thought (or at least shown) in the course apart from basic algebra. Do you think logs enter this definition? Since I most definitly remeber nothing about them from high school... |
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Nov 20 |
asked | Proving $0$ is the limit of $\frac{n}{2^n-1}$ from definition alone |
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Nov 19 |
comment |
Proving a vector space over itself have no subspaces Thanks for the edits! English is not my mother language so translating is sometimes difficult for me. |
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Nov 19 |
comment |
Proving a vector space over itself have no subspaces Ok, that did help me. I now know that if $1_F\in U$ it can't be a vector subspace. But I'm not sure what happens if $1_F\notin U$, since the axioms for vector spaces don't require a vector identity element, right? |
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Nov 19 |
asked | Proving a vector space over itself have no subspaces |
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Nov 14 |
accepted | Proving the sup of $\{\frac{n-m}{n+m}|n,m\in \mathbb{N}, m<n\}$ |
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Nov 14 |
comment |
Proving the sup of $\{\frac{n-m}{n+m}|n,m\in \mathbb{N}, m<n\}$ Though I see how I can use it in this question, appereantly it wasn't necessery. Thanks for this neat idea though, I'm sure it will be useful for me in the future. |
