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 Yearling
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2d
comment Does Russel's paradox preclude us from using the power set to generate every possible set?
Well as far as I understand, "the set of all things" is not a set, you can't just say "I take everything and call it $A$", and there is actually quite a delicate process describing what is or isn't a set.
2d
comment Fixed point of a differentiable function on a closed interval
@cantorhead, oh well that makes it easy. Thanks!
2d
comment Fixed point of a differentiable function on a closed interval
@GitGud Oh oops, fixed
2d
revised Fixed point of a differentiable function on a closed interval
added 1 character in body; added 2 characters in body
2d
asked Fixed point of a differentiable function on a closed interval
Apr
14
comment Finding a counter example for $ \left(A+A\right)'\subseteq\left(A'+A\right)\cup\left(A'+A'\right)$
I thought about the idea of searching for a set $A$ with no limit points, such that $A+A$ will have a limit point, but wasn't able to figure one out myself. Even the solution you gave took me quite a while to understand, but I get it now. Thanks!
Apr
14
accepted Finding a counter example for $ \left(A+A\right)'\subseteq\left(A'+A\right)\cup\left(A'+A'\right)$
Apr
14
asked Finding a counter example for $ \left(A+A\right)'\subseteq\left(A'+A\right)\cup\left(A'+A'\right)$
Apr
12
accepted Different definitions of limit points?
Apr
7
asked Different definitions of limit points?
Apr
3
comment Why can you place in the recursive definition to find the limit?
That makes everything clear. Thank you very much!
Apr
3
accepted Why can you place in the recursive definition to find the limit?
Apr
3
asked Why can you place in the recursive definition to find the limit?
Apr
1
awarded  Yearling
Apr
1
comment Finding the limit of $\sqrt[n]{{kn \choose n}}$
Got it! Thanks!
Apr
1
accepted Finding the limit of $\sqrt[n]{{kn \choose n}}$
Apr
1
comment Finding the limit of $\sqrt[n]{{kn \choose n}}$
Not quite sure about how you simplified the last step, will try it by hand and come back :P
Apr
1
comment Finding the limit of $\sqrt[n]{{kn \choose n}}$
unfortunately I am unable to follow most of proof 1, and in proof 2 I'm not sure how the lemma gives that $\lim \frac{(kn)!^{1/n}}{(kn)^k} = e^{-k}$, or how you did the algebra...
Apr
1
asked Finding the limit of $\sqrt[n]{{kn \choose n}}$
Mar
30
awarded  Critic