Nescio
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 Apr23 comment Does Russel's paradox preclude us from using the power set to generate every possible set? Well as far as I understand, "the set of all things" is not a set, you can't just say "I take everything and call it $A$", and there is actually quite a delicate process describing what is or isn't a set. Apr23 comment Fixed point of a differentiable function on a closed interval @cantorhead, oh well that makes it easy. Thanks! Apr23 comment Fixed point of a differentiable function on a closed interval @GitGud Oh oops, fixed Apr23 revised Fixed point of a differentiable function on a closed interval added 1 character in body; added 2 characters in body Apr23 asked Fixed point of a differentiable function on a closed interval Apr14 comment Finding a counter example for $\left(A+A\right)'\subseteq\left(A'+A\right)\cup\left(A'+A'\right)$ I thought about the idea of searching for a set $A$ with no limit points, such that $A+A$ will have a limit point, but wasn't able to figure one out myself. Even the solution you gave took me quite a while to understand, but I get it now. Thanks! Apr14 accepted Finding a counter example for $\left(A+A\right)'\subseteq\left(A'+A\right)\cup\left(A'+A'\right)$ Apr14 asked Finding a counter example for $\left(A+A\right)'\subseteq\left(A'+A\right)\cup\left(A'+A'\right)$ Apr12 accepted Different definitions of limit points? Apr7 asked Different definitions of limit points? Apr3 comment Why can you place in the recursive definition to find the limit? That makes everything clear. Thank you very much! Apr3 accepted Why can you place in the recursive definition to find the limit? Apr3 asked Why can you place in the recursive definition to find the limit? Apr1 awarded Yearling Apr1 comment Finding the limit of $\sqrt[n]{{kn \choose n}}$ Got it! Thanks! Apr1 accepted Finding the limit of $\sqrt[n]{{kn \choose n}}$ Apr1 comment Finding the limit of $\sqrt[n]{{kn \choose n}}$ Not quite sure about how you simplified the last step, will try it by hand and come back :P Apr1 comment Finding the limit of $\sqrt[n]{{kn \choose n}}$ unfortunately I am unable to follow most of proof 1, and in proof 2 I'm not sure how the lemma gives that $\lim \frac{(kn)!^{1/n}}{(kn)^k} = e^{-k}$, or how you did the algebra... Apr1 asked Finding the limit of $\sqrt[n]{{kn \choose n}}$ Mar30 awarded Critic